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snow_tiger [21]

3 years ago

12

A 14-gauge copper wire of diameter 1.628 mm carries a current of 12.5 What is the potential difference across a 2.00 - m length

of the wire? *p=1.47x10^-8

1 answer:

Dvinal [7]3 years ago

7 0

Answer:

$V=1.76\times 10^{-4}\ V$

Explanation:

Given that,

The diameter of a wire, d = 1.628 mm

Radius, r = 0.814 mm = 0.000814m

Current, I = 12.5 mA

The length of the wire, l = 2m

The resistivity of the wire, $\rho=1.47\times 10^{-8}\ \Omega-m$

We need to find the potential difference across the wire. We know that the resistance of the wire is given by :

$R=\rho\dfrac{l}{A}$

Also, V = IR

$\dfrac{V}{I}=\rho\dfrac{l}{A}\\\\V=\dfrac{\rho l I}{A}\\\\V=\dfrac{1.47\times 10^{-8}\times 2\times 12.5\times 10^{-3}}{\pi \times (0.000814)^2}\\\\V=1.76\times 10^{-4}\ V$

So, the potential difference of the wire is $1.76\times 10^{-4}\ V$ .

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What is one watt ? Write the relation of watt with kilowatt , megawatt , and horsepower .

alina1380 [7]

Answer:

See the explanation below

Explanation:

The watt (the power) is equal to the relationship between the work and the time in which that work is performed.

$P = W/t$

where:

W = work [J] (units of Joules)

t = time [s].

Now 1000 [W] are equal to 1 [kW]

And 1000000 [W] are equal to 1 [MW]

The horsepower is the unit of power in the imperial system of units.

And 745.7 [W] are equal to 1 [Hp]

3 0

3 years ago

Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di

jeyben [28]

<u>Answer :</u>

(a) d = 0.25 m

(b) d = 0.5 m

<u>Explanation :</u>

It is given that,

Frequency of sound waves, f = 686 Hz

Speed of sound wave at $20^0\ C$ is, v = 343 m/s

(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

$d=\dfrac{\lambda}{2}$ ........(1)

Velocity of sound wave is given by :

$v=f\times \lambda$

$d=\dfrac{v}{2f}$

$d=\dfrac{343\ m/s}{2\times 686\ Hz}$

$d=0.25\ m$

Hence, when the speakers are in phase the smallest distance between the speakers for which the interference of the sound waves is perfectly destructive is 0.25 m.

(2) For constructive interference, the path difference is integral multiple of wavelengths i.e.

$d=n\lambda$ ( n = integers )

Let n = 1

So, $d=\dfrac{v}{f}$

$d=\dfrac{343\ m/s}{686\ Hz}$

$d=0.5\ m$

Hence, the smallest distance between the speakers for which the interference of the sound waves is maximum constructive is 0.5 m.

4 0

4 years ago

Read 2 more answers

If a 20 kg green fish swimming at 2 m/s swallows a 1 kg orange fish at rest, in what direction, and how fast

krok68 [10]

Answer: 1.9 m/s

Explanation:

The question should be:

If a 20 kg green fish swimming at 2 m/s swallows a 1 kg orange fish at rest, in what direction, and how fast will the green fish swim after eating the orange fish?

Ok, here we have conservation of momentum.

At the beginning, the total momentum is equal to the sum between the momentum of the green fish and the momentum of the orange fish.

Where the momentum is written as:

P = m*v

m = mass

v = velocity.

The momentum of the green fish is:

Pg = 20kg*2m/s = 40 kg*m/s.

The momentum of the orange fish is:

Po = 1kg*0m/s = 0

The total initial momentum is:

Pi = Pg + Po = 40 kg*m/s.

After the green fish eats the orange fish, we do not have an orange fish anymore, and the mass of the green fish will be equal to it's initial mass, plus the mass of the fish that it ate, this will be:

M = 20kg + 1kg = 21kg.

Then the momentum will be:

Pf = 21kg*V

Where V is the final velocity.

For conservation of momentum, the initial momentum is equal to the final momentum, then:

Pi = Pf

40 kg*m/s = 21kg*V

(40/21) m/s = 1.9 m/s = V

The fish's final velocity is 1.9 m/s

5 0

3 years ago

How much current must flow through a wire to make a magnetic field as strong as Earth's field (5.00 x 10^-5 T) 1.00 m away from

torisob [31]

Answer:

250 A

Explanation:

B = 5 x 10^-5 T, r = 1 m

Let current be i.

the magnetic field due to a straight current carrying conductor is given by

B = μ0 / 4π x 2i / r

5 x 10^-5 = 10^-7 x 2 x i / 1

i = 250 A

7 0

3 years ago

An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed, w

Dovator [93]

The elephant and the mouse having zero weight in a gravity free space will not bump into you at the same effect.

<u>Explanation: </u>

When both are in a gravity free space, the weights are zero, as we know that the $\text {weight of the body}=\text {mass of the body} \times \text {acceleration due to gravity}$

$\text {here, the weight of elephant}=\text {mass of elephant } \times \text {zero gravti} y=zero$

$\text {similarly,weight of mouse}=\text {mass of mouse } \times \text {zero gravity}=zero$

But when they will acquire the speed of same magnitude, say v, their different masses will acquire different momentum, which will make the difference in effect while bumping.

$\text { momentum of elephant }=\text { mass of elephant } \times v$ $\text { momentum of mouse = mass of mouse } \times v$

And as we know $\text { mass of elephant }>\text { mass of mouse }$ Therefore, effect of impact by elephant will be more than that of mouse . An elephant breaking into you will take you back faster than a mouse in space hits you.

8 0

3 years ago