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2 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST EXTRA POINTS.. IM GIVING 40 POINTS !! DONT SKIP :((.

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

7 0

Answer:

y = 1x + 46

Step-by-step explanation:

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What is 6x3-69+12x4-7x(9x3)+7-1?

aksik [14]

Answer:

Step-by-step explanation:

6 times 3 is 18 so.. 18 minus 69 would be -36 plus 12 is a positive 1 times 14 would be 14 minus 7 would be 7 7 times 27 would 38 plus 7 would be 45 minus one would be 44

4 0

3 years ago

Read 2 more answers

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

3 years ago

Will get branliest!!!!!!!

lawyer [7]

Answer:

It has the same domain as the function $f(x)=-\sqrt{-x}$

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand cannot be a negative number

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

Verify each statement

Part 1) It has the same domain as the function $f(x)=-\sqrt{-x}$

The statement is true

The domain of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 2) It has the same range as the function $f(x)=-\sqrt{-x}$

The statement is false

The range of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function $f(x)=-\sqrt{x}$

The statement is false

The domain of the function $f(x)=-\sqrt{x}$ is

the interval ---> [0,∞)

Part 4) It has the same range as the function $f(x)=-\sqrt{x}$

The statement is false

The range of the function $f(x)=-\sqrt{x}$ is

the interval ---> (-∞,0]

4 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!! WILL GIVE BRAINLIEST!!!!

wel

Answer:

1. 1023

2. 8

3. The 7th Term

Step-by-step explanation:

7 0

3 years ago

7,110 round to nearest thousand place

Valentin [98]

10 000

Anything greater than 5 rounds up

Hope this helps :)

6 0

3 years ago

Read 2 more answers

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. IM GIVING 40 POINTS !! DONT SKIP :((.

PLEASE HELP !! ILL GIVE BRAINLIEST EXTRA POINTS.. IM GIVING 40 POINTS !! DONT SKIP :((.