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Naddika [18.5K]
2 years ago
9

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. IM GIVING 40 POINTS !! DONT SKIP :((.

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
7 0

Answer:

y = 1x + 46

Step-by-step explanation:

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What is 6x3-69+12x4-7x(9x3)+7-1?
aksik [14]

Answer:

44

Step-by-step explanation:

6 times 3 is 18 so.. 18 minus 69 would be -36 plus 12 is a positive 1 times 14 would be 14 minus 7 would be 7 7 times 27 would 38 plus 7 would be  45 minus one would be 44

4 0
3 years ago
Read 2 more answers
Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

Let us solve the equation by completing the square

x^2-12x\:=\:21

Add (-6)² to both sides

x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2

simplify

x^2-12x+\left(-6\right)^2=57

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

Therefore, the solutions to the quadratic equation will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

5 0
3 years ago
Will get branliest!!!!!!!​
lawyer [7]

Answer:

It has the same domain as the function f(x)=-\sqrt{-x}

Step-by-step explanation:

we have

f(x)=\sqrt{-x}

we know that

The radicand cannot be a negative number

so

-x\geq 0

Solve for x

Multiply by -1 both sides

x\leq 0

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

<u><em>Verify each statement</em></u>

Part 1) It has the same domain as the function f(x)=-\sqrt{-x}

<em>The statement is true</em>

The domain of the function f(x)=-\sqrt{-x} is

the interval ---> (-∞,0]

Part 2) It has the same range as the function f(x)=-\sqrt{-x}

The statement is false

The range of the function f(x)=-\sqrt{-x} is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function f(x)=-\sqrt{x}

The statement is false

The domain of the function f(x)=-\sqrt{x} is

the interval ---> [0,∞)

Part 4) It has the same range as the function f(x)=-\sqrt{x}

The statement is false

The range of the function f(x)=-\sqrt{x} is

the interval ---> (-∞,0]

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!! WILL GIVE BRAINLIEST!!!!
wel

Answer:

1. 1023

2. 8

3. The 7th Term

Step-by-step explanation:

7 0
3 years ago
7,110 round to nearest thousand place
Valentin [98]
10 000

Anything greater than 5 rounds up 

Hope this helps :)
6 0
3 years ago
Read 2 more answers
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