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aliya0001 [1]
4 years ago
6

Write a net ionic equation to show that hydrofluoric acid , hf , behaves as an acid in water.

Chemistry
1 answer:
Montano1993 [528]4 years ago
6 0
This equation shows how HF, hydrofluoric acid behaves in water. 
HF (aq) ----> H+ (aq) + F- (aq). In water acids will dissociate into positive cations and negative anions. The strength or weakness of an acid depends on its ability to dissociate in water. Substances that dissociate completely are strong acids while partial dissociation indicates a weak acid. HF is considered to be a weak acid because it does not completely dissociates in water. There is instead an equilibrium between HF molecules and the dissociates. 
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They break down rotting materials and return nutrients to the soil.

( They don't do photosynthesis since they are much different from plants)

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Airida [17]

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<h3>What is Gambling ? </h3>

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<h3>What are the effects of gambling disorder ?</h3>

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6 0
1 year ago
If 0.00872 mol neon gas at a particular temperature and pressure occupies a volume of 211 mL, what volume would 0.00701 mol neon
GuDViN [60]

Answer:

0.00701 moles of neon gas will occupy 170 ml of volume under the same conditions.

Explanation:

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

We are given:

V_1=211 mL\\n_1=0.00872 mol\\V_2=?\\n_2=0.00701 mol

Putting values in above equation, we get:

\frac{211 mL}{0.00872 mol}=\frac{V_2}{0.00701}

V_2=\frac{211 mL\tomes 0.00701 mol}{0.00872 mol}=169.62 mL\approx 170 mL

0.00701 moles of neon gas will occupy 170 ml of volume under the same conditions.

3 0
3 years ago
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Sedaia [141]
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5 0
3 years ago
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Determine the volume in liters occupied by 22.6 g of I2 gas at STP.
AleksandrR [38]

 The volume in liters  occupied  by 22.6 g  of I₂  gas  at STP  is  1.99 L (answer A)

 <u><em>calculation</em></u>

Step: find the  moles of I₂

moles= mass÷  molar mass

from  periodic table the  molar mass  of I₂  is  253.8 g/mol

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Step 2:find the volume  of I₂  at STP

At STP  1  moles =22.4 L

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<em>by cross  multiplication</em>

={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L


6 0
4 years ago
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