Answer:
Option d is correct = Negative ion
Explanation:
We know that an atom consist of electrons, protons and neutrons. Neutrons and protons are present inside the nucleus while electrons are present out side the nucleus. Electron has a negative charge and is written as e⁻. The mass of electron is 9.10938356×10⁻³¹ Kg
. While mass of proton and neutron is 1.672623×10⁻²⁷Kg and 1.674929×10⁻²⁷ Kg respectively.
Symbol of proton= P⁺
Symbol of neutron= n⁰
The number of electron or number of protons are called atomic number while mass number of an atom is sum of protons and neutrons. The umber of protons and electrons are always equal to make the atom electrically neutral and when an atom loses its valance electron the number of protons increases and thus positive charge increased and atom form cation.
When an atom gain electron negative charge increase because of more number of electron thus atom form negative ion or anion. For example,
Anion formation:
X + e⁻ → X⁻
Cation formation:
X → X⁺ + e⁻
Thus option d is correct option.
The result of Rutherford's gold foil experiment was that most of the particles went straight through the foil without being deflected.
However, a few of the particles were deflected by relatively large angles.
Answer : The value of
of the weak acid is, 4.72
Explanation :
First we have to calculate the moles of KOH.


Now we have to calculate the value of
of the weak acid.
The equilibrium chemical reaction is:

Initial moles 0.25 0.03 0
At eqm. (0.25-0.03) 0.03 0.03
= 0.22
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[HK]}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BHK%5D%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:


Therefore, the value of
of the weak acid is, 4.72
the 1st one is balanced, the 2nd isn't (the number of Mg differs from left 1 to right 2).
The third is also not balanced, 2 F left,2*3=6 on the right
Answer:
pH

OH- concentration 28.84
Explanation:
KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1
In any aqueous solution, the H3O+ and OH - must satisfy the following condition -
![[ H_3O^+] [OH^-] = k_w](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%5BOH%5E-%5D%20%3D%20k_w)
![[ H_3O^+] = \frac{k_w}{ [OH^-]}](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%3D%20%5Cfrac%7Bk_w%7D%7B%20%5BOH%5E-%5D%7D)
M
pH =
![- log [ H_3O^+]\\- log [2.857 * 10^{-13}]](https://tex.z-dn.net/?f=-%20log%20%5B%20H_3O%5E%2B%5D%5C%5C-%20log%20%5B2.857%20%2A%2010%5E%7B-13%7D%5D)
pH
![= - [-12.54]\\= 12.54](https://tex.z-dn.net/?f=%3D%20-%20%5B-12.54%5D%5C%5C%3D%2012.54)
pOH
pH
pOH

OH concentration 
OH- concentration 28.84