2SO2 + O2 ------> 2SO3
1) M(SO2)= 32.0 + 2*16.0 = 64 g/mol
2) 100.0 g SO2 * 1 mol SO2/64 g SO2 = 1.5625 mol SO2
3) 2SO2 + O2 ------> 2SO3
2 mol 1 mol
1.5625 mol x mol
x= 1.5625/2=0.78125 ≈ 0.7813 mol O2
Answer: 0.7813 mol O2.
Answer:
The order of some common metals in the electromotive series, starting with the most easily oxidized, is: lithium, potassium, calcium, sodium, magnesium, aluminum, zinc, chromium, iron, cobalt, nickel, lead, hydrogen, copper, mercury, silver, platinum, and gold.
Explanation:
The correct equilibrium expression would be one that has products over reactants, and to the power of their stoichiometric coefficient. Also, it would not include any liquids or solids.
The equilibrium expression for your balanced reaction is:
All elements can be classified as metals, metalloids, or nonmetals