Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² / 0,8 mol/L - x.
solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.
The molecules of hydrogen gas that are formed is when 48.7 g of sodium are added to water is 6.375 x 10²³ molecules
<u><em>calculation</em></u>
2 Na +2H₂O → 2 NaOH +H₂
Step 1: find the moles of sodium (Na)
moles =mass÷ molar mass
from periodic table the molar mass of Na = 23 g/mol
moles= 48.7 g÷ 23 g/mol =2.117 moles
Step 2:use the mole ratio to determine the moles of H₂
from given equation Na:H₂ is 2:1
therefore the moles of H₂ = 2.117 moles x 1/2=1.059 moles
Step 3: find the molecules of H₂ using the Avogadro's law
According to Avogadro's law 1 mole = 6.02 x 10²³ molecules
1.059 moles = ? molecules
by cross multiplication
= [(1.059 moles x 6.02 x10²³ molecules) / 1 mole] =6.375 x 10²³ molecules
The dilution factor of the unknown sample is 10. The dilution factor of a solution refers to the ratio of the final volume of the now diluted solution to the initial volume of the of the initial concentrated solution.
Mathematically;
The dilution factor is given by the formula;
Dilution factor = Final volume of the now diluted solution/ Initial volume of more concentrated solution
Final volume of the now diluted solution = 100.0 ml
Initial volume of more concentrated solution = 10.00 ml
Dilution factor = 100.0 ml/10.00 ml
Dilution factor = 10
Learn more: brainly.com/question/20113402
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(215 torr)(51 mL)=("x" torr)(18,500 mL) x = O.593 torr
Answer:
I think the primary producers start the flow of energy
