Answer:
Volume of 22 drop will be 0.68 ml
Explanation:
We have given volume of one drop = 0.031 ml
We know that 1 liter = 1000 ml
So 
So 0.031 ml will be equal to 
We have to find the volume of 22 drop
For finding volume of 22 drop we have to multiply volume of one drop by 22
So volume of 22 drop will be 
So volume of 22 drop will be 0.68 ml
<h2>
Answer:50
</h2>
Explanation:
Let
be the airspeed.
Let
be the cross wind speed.
We know that,ground speed is the vector sum of airspeed and cross wind speed and airspeed is perpendicular to cross wind speed.
If
and
are two perpendicular vectors,the resultant vector has the magnitude 
Given,

So,the ground speed is 
The density of the object is 0.032 g/cm^3.
<h3>What is density?</h3>
The term density means the ratio of the mass to the volume of an object. Now we know that when an object is dense that it would sink to the bottom of a fluid.
Now given that;
Mass = 0.8 g
volume= 25 cm^3
Density = mass/volume
Density = 0.8 g / 25 cm^3
= 0.032 g/cm^3
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MISSING PARTS
What is the density of an object having a mass of
0.8g and a volume of 25cm^3
The work function in eV for the given cutoff frequency is 5.05 eV.
<h3>What is cutoff frequency?</h3>
The work function is related to the frequency as
Wo = h x fo
where, fo = cutoff frequency and h is the Planck's constant
Given is the cutoff frequency for a certain element is 1.22 x 10¹⁵ Hz
Wo = 6.626 x 10⁻³⁴ x 1.22 x 10¹⁵ Hz / 1.6 x 10⁻¹⁹
Wo = 5.05 eV
Thus, the work function is 5.05 eV
Learn more about cutoff frequency.
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Answer:
To make an inference what needs to be in the text in the order for you is explained below in complete details.
Explanation:
Making an inference requires using what you recognize to guess what you don't understand or understanding between the series. Scholars who make inferences use the evidence in the text along with their own practices to encourage them to figure out what is not straight said, making the text special and remarkable.