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3 years ago

Calculate the speed above.

Physics

1 answer:

Fynjy0 [20]3 years ago

5 0

1. 0.83ms-1

2. The motion described in the graph is variable motion i.e. variable velocity because the curve of graph is parabolic

3. Straight line parallel to time axis

4. No

Inform me if i am answering correct

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A crowbar having the length of 1.75m is used to balance a load between the fulcrum and the load is 0.5m calculate MA

aliina [53]

Answer:

1.70

Explanation:

substract 1.75-0.5

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3 years ago

Compared to Jupiter, Saturn's atmosphere is more uniform with no significant variation in color in the lower cloud levels. much

creativ13 [48]

Answer:

Explained

Explanation:

Compared to Jupiter, Saturn's atmosphere is more calm with fewer disturbances or storms.

The Atmosphere in Jupiter is highly violent and thinner as compared with Saturn.

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3 years ago

A series LR circuit contains an emf source of 19 V having no internal resistance, a resistor, a 22 H inductor having no apprecia

masha68 [24]

Answer: R = 394.36ohm

Explanation: In a LR circuit, voltage for a resistor in function of time is given by:

$V(t) = \epsilon. e^{-t.\frac{L}{R} }$

ε is emf

L is indutance of inductor

R is resistance of resistor

After 4s, emf = 0.8*19, so:

$0.8*19 = 19. e^{-4.\frac{22}{R} }$

$0.8 = e^{-\frac{88}{R} }$

$ln(0.8) = ln(e^{-\frac{88}{R} })$

$ln(0.8) = -\frac{88}{R}$

$R = -\frac{88}{ln(0.8)}$

R = 394.36

In this LR circuit, the resistance of the resistor is 394.36ohms.

7 0

3 years ago

The skateboarder starts at the top of the ramps, and rolls down and back up the other side. Which graph shows the most Kinetic E

DaniilM [7]

Answer:

Explanation:

Usually when you are at the bottom you are at peak speed. It also shows that Kinetic Energy is the green bar and in picture C the green bar is highest.

6 0

3 years ago

Two long parallel wires are separated by forty centimeters and carry oppositely-directed currents of ten amperes. Find the magni

Softa [21]

Answer:

1.04μT

Explanation:

Due to both wires have opposite currents, the magnitude of the total magnetic field is given by

$B_T=\frac{\mu_o I}{2 \pi r_1}-\frac{\mu_o I}{2 \pi r_2}$

I: electric current = 10A

mu_o: magnetic permeability of vacuum = 4pi*10^{-7} N/A^2

r1: distance from wire 1 to the point in which B is measured.

r2: distance from wire 2.

The distance between wires is 40cm = 0.4m. Hence, r1=0.2m r2=0.6m

By replacing in the formula you obtain:

$B_T=\frac{(4\pi *10^{-7}N/A^2)(10A)}{2\pi}(\frac{1}{0.4m}-\frac{1}{0.6m})=1.04*10^{-6}T =1.04\mu T$

hence, the magnitude of the magnetic field is 1.04μT

4 0

4 years ago