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Aneli [31]
3 years ago
7

Calculate the speed above.

Physics
1 answer:
Fynjy0 [20]3 years ago
5 0
1. 0.83ms-1

2. The motion described in the graph is variable motion i.e. variable velocity because the curve of graph is parabolic

3. Straight line parallel to time axis

4. No

Inform me if i am answering correct
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A proton is moving at 425 m/s. (a) How much work must be done on it to stop it? (A proton has a mass of 1.67×10−27 kg.) (b) Assu
Tpy6a [65]

Answer:

a)1.51*10^-22joules b) 1.89*10^-7m

Explanation:

Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules

b) net force acting to stop the proton = 8.01*10^-16

Work done needed to stop the proton = net force acting opposite the motion * distance

Distance covered = need work done/ net force

Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m

8 0
4 years ago
Microwave ovens emit microwave energy with a wavelength of 12.3 cm. What is the energy of exactly one photon of this microwave r
Valentin [98]
The energy of a photon is proportional to the speed of light and inversely proportional to the wavelength. The constant of proportionality is Planck's constant, <span>6.626 * 10^-34 Js</span>

E = hc/ {wavelength} 
E = [ 6.626 * 10^-34 Js * 2.997 * 10^8 m/s ] / 0.124 m 
E = 1.60 * 10^-24 J
4 0
3 years ago
Read 2 more answers
Suppose you were examining a pulsing radio signal from a stellar remnant in a distant part of the Milky Way. Knowing that ionizi
Solnce55 [7]

Answer:

- Time delta is associated with difference in wavelengths

Explanation:

When pulsating radio waves consisting of different wavelengths pass through the ionized gas in interstellar space, the fast oscillating radio waves travel relatively faster than the slowly oscillating radio waves. As a result radio waves get dispersed and there is a time difference between the radio waves with different wavelength when the pulses arrive.

5 0
4 years ago
In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above
diamong [38]

Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

Ymax = \frac{Vo^2}{2g}

Since we are told that Ya = 4Yb:

Ya =  \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}

Simplifying the equation:

Va^2 = 4*Vb^2

Va = 2*Vb

5 0
3 years ago
You are fixing a transformer for a toy truck that uses an 8.0-V emf to run it. The primary coil of the transformer is broken; th
Art [367]

Answer:

a. The primary turns is 60 turns

b. The secondary voltage will be 360 volts.

Explanation:

Given data

secondary turns N2= 40 turns

primary turns N1= ?

primary voltage V1= 120 volts

secondary voltage V2= 8 volts

Applying the transformer formula which is

\frac{N1}{N2} =\frac{V1}{V2}

we can solve for N1 by substituting into the equation above

\frac{N1}{40} =\frac{120}{8} \\\ N1= \frac{40*120}{8} \\\ N1= \frac{4800}{8} \\\ N1= 60

the primary turns is 60 turns

If the primary voltage is V1 240 volts hence the secondary voltage V2 will be (to get the voltage of the secondary coil using emf substitute the values of the previously gotten N1 and N2 using V1 as 240 volts)

\frac{40}{60} =\frac{240}{V2}\\\\V2= \frac{60*240}{40} \\\\V2=\frac{ 14400}{40} \\\\V2= 360

the secondary voltage will be 360 volts.

6 0
3 years ago
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