Water is an essential part of life and its availability is important for all living creatures. On the other side, the world is suffering from a major problem of drinking water. There are several gases, microorganisms and other toxins (chemicals and heavy metals) added into water during rain, flowing water, etc. which is responsible for water pollution. This review article describes various applications of nanomaterial in removing different types of impurities from polluted water. There are various kinds of nanomaterials, which carried huge potential to treat polluted water (containing metal toxin substance, different organic and inorganic impurities) very effectively due to their unique properties like greater surface area, able to work at low concentration, etc. The nanostructured catalytic membranes, nanosorbents and nanophotocatalyst based approaches to remove pollutants from wastewater are eco-friendly and efficient, but they require more energy, more investment in order to purify the wastewater. There are many challenges and issues of wastewater treatment. Some precautions are also required to keep away from ecological and health issues. New modern equipment for wastewater treatment should be flexible, low cost and efficient for the commercialization purpose.
The hydroxide (OH) in the metallic hydroxide will react with the hydrogen in an acid to form H2O. The remaining ions will combine to form a salt. Therefore a metal hydroxide and an acid will form a salt + water.
Not 100%, but I think it would be 0.0013 because the equation for Molarity is Moles of solute(Mol)/ Liters of solution(L)
Answer:
balanced equation of glucose
6CO2 + 6H2O----------C6H12O6 + 6O2
in the presence of sun light.
Answer:
Percent Yield = 91.97%
Explanation:
Aluminum hydroxide Formula: Al(OH)3 Molar mass: 78 g/mol
Stomach acid Formula: HCl Molar mass: 36.46 g/mol
Aluminum Chloride Formula: AlCl₃ Molar mass: 133.34 g/mol
14g Al(OH)3
2Al(OH)3 + Cl2 → 2Al(OH)3Cl
Balanced equation
14/156 = 0.0897 Moles of Al(OH)3
Ratio is 2:1:2 so same ratio for Al(OH)3 to AlCl₃
0.0897 x 266.68 = 23.92grams of AlCl₃
Theoretical yield of aluminum chloride
Actual yield aluminum chloride 22.0 g
Percent yield?
Percent Yield = (actual Yield/Theoretical yield) x 100
Percent Yield = (22/23.92) x 100
Percent Yield = 91.97%