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Allushta [10]
2 years ago
11

Object 1 is undergoing uniform circular motion at a radius of 10 cm. Object 2 is undergoing uniform circular motion at a radius

of 0.2 m. If the objects have the same mass and are traveling with the same speed, which object is experiencing the larger centripetal force and why
Physics
1 answer:
ElenaW [278]2 years ago
3 0

Answer:

The first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.

Explanation:

Given;

radius of the first object, r₁ = 10 cm = 0.1 m

radius of the second object, r₂ = 0.2 m

let the mass of the two objects, = m

let the speed of the two objects = v

The centripetal force of the first object is given by;

F_c_1 = \frac{mv^2}{r_1} \\\\F_c_1 = \frac{mv^2}{0.1}\\\\F_c_1 =  10mv^2

The centripetal force of the second object is given by;

F_c_2 = \frac{mv^2}{r_2} \\\\F_c_2 = \frac{mv^2}{0.2}\\\\F_c_1 =  5mv^2

Therefore, the first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.

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Un the way to the moon, the Apollo astro-
kherson [118]

Answer:

Distance =  345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2}  } \\

F_{m} =G*\frac{m_{m}*m_{a}  }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]

When we match these equations the masses cancel out as the universal gravitational constant

G*\frac{m_{e} *m_{a} }{r_{e}^{2}  } = G*\frac{m_{m} *m_{a} }{r_{m}^{2}  }\\\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2}  }

To solve this equation we have to replace the first equation of related with the distances.

\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m}  )^{2}  } = \frac{7.36*10^{22}  }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17}  \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c }  }{2*a}\\  where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) }  }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

<u>Second part</u>

<u />

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2}  } \\a=3.33*10^{19} [m/s^2]

6 0
3 years ago
Why do the noble gases and some other elements on the right side of the periodic table occur as gases instead of solids as do th
mash [69]

Explanation:

The left side of the periodic table has elements that have less number of electrons in the valence shell.

These elements loose electrons easily.These elements appear as metals or metalloids in nature.These are hard solids.Their inter molecular forces are very strong.

The right side of the periodic table has elements that have more number of electrons in the valence shell.

These elements gain electrons easily.These elements appear as non metals most of which are gases.Their inter molecular forces are weak.

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Explain how heat (thermal energy) can change the motion (kinetic energy) of the particles in objects.
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Answer:

Adding heat makes the particles move faster so the particles have more kinetic energy when more thermal energy is added

Explanation:

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1<br> 2<br> 3<br> What would happen if Bulb 1 goes out?
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Answer:

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Explanation:

because it will explode

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Answer:

1500 m/s

Explanation:

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Speed = frequency x wavelength

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simply substitute into above equation

Speed = 500 Hz x 3m

= 1500 m/s

6 0
3 years ago
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