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Allushta [10]
3 years ago
11

Object 1 is undergoing uniform circular motion at a radius of 10 cm. Object 2 is undergoing uniform circular motion at a radius

of 0.2 m. If the objects have the same mass and are traveling with the same speed, which object is experiencing the larger centripetal force and why
Physics
1 answer:
ElenaW [278]3 years ago
3 0

Answer:

The first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.

Explanation:

Given;

radius of the first object, r₁ = 10 cm = 0.1 m

radius of the second object, r₂ = 0.2 m

let the mass of the two objects, = m

let the speed of the two objects = v

The centripetal force of the first object is given by;

F_c_1 = \frac{mv^2}{r_1} \\\\F_c_1 = \frac{mv^2}{0.1}\\\\F_c_1 =  10mv^2

The centripetal force of the second object is given by;

F_c_2 = \frac{mv^2}{r_2} \\\\F_c_2 = \frac{mv^2}{0.2}\\\\F_c_1 =  5mv^2

Therefore, the first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.

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Given that:

     Force (F) = 8 N,

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determine magnitude of net force (Fnet) = ?

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                                           = sq.root [(7.72)² + (2.07)²]

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The block exerts a force F on the dart that is proportional to the dart’s velocity v and in the opposite direction, that is F =
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Answer:

s = mV/2b

Assumptions: 1. the darts finally velocity is zero

2. The force being exerted on the dart by the block is constant and so the dart moves through the block with constant acceleration in the opposite direction. (Newton's second law)

3. Since the acceleration of the dart through the block is constant, then the equations of constant acceleration motion apply to the motion of the dart through the block.

Explanation:

Let a = acceleration of the dart through the block

V = velocity of the dart

m = mass of the dart

Vf = finally velocity of the dart

S = distance traveled by the dart through the block.

From Newton's second law of motion which states that the acceleration of a body is in the same direction as the net force acting on the body and is equal to the force divided by the mass. That is F = ma

Also F = -bv ........(1)

Therefore -bv = ma........(2)

From the equals of constant acceleration motion, Vf² = V² + 2aS

Vf = 0

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-2aS = V²

a = -V² / 2S

Substituting this expression for a in

Equation (2) above

-bV = m( - V²/2S)

On rearranging,

S = mV/2b

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