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juin [17]
3 years ago
15

In which orbitals would the valence electrons for selenium (Se) be placed?

Chemistry
1 answer:
SOVA2 [1]3 years ago
6 0
The valence electrons of Selenium (Se) would be placed in the s and p orbitals.

Hope I could help!
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How many neutrons does beryllium have?
PilotLPTM [1.2K]
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6 0
2 years ago
Does anyone know how to do this?
Sloan [31]

Answer

find out the number of moles and use the molar ratio (numbers in front of formulas (in this case they are all 1) to determine how many moles of each product you are going to get theoretically

n=m/M is the equation to use to get moles here

30.8 gm/32.04 g/mol=0.9612 moles of the methanol and also of the formaldehyde so

0.9612 moles of the formaldehyde x molar mass (M) 30.73 g/mol= 29.54 gm which is the theoretical yield you already have the actual yield of 24.7 gm

then divide the actual by the theoretical to get the % yield which is 83.6%

Explanation:

4 0
3 years ago
Describe some acidic oxides that can be prepared by thermal decomposition of nitrates and carbonates
azamat

When calcium carbonate is heated, it breaks down to form calcium oxide and carbon dioxide.

Thermal decomposition is the process in which heat is required.

It is also known as thermolysis.

It is processed in which a compound breaks into two or more products when the heat is supplied.

This reaction is used for the production of oxygen.

This reaction is also used for production of acidic as well as basic oxides.

CaCO3 on thermal decomposition gives:

CaCO3→CaO+CO2

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CO2→ Acidic oxide.

6 0
3 years ago
25 POINTS!
ryzh [129]

Answer: The Answer is B. Energy can not be created nor destroyed.

Explanation:

4 0
3 years ago
128.3 grams of methane (CH4) is equal to how many moles of methane
Neko [114]
About 8.0 moles of methane.Number of moles = MassMolar mass.

And thus we get the quotient:

128.3⋅g16.04⋅g⋅mol−1=8.0⋅moles of methane.

Note that the expression is dimensionally consistent, we wanted an answer in moles, and the quotients gives, 1mol−1=11mol=mol as required.

6 0
3 years ago
Read 2 more answers
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