Answer:
12.26%
Explanation:
MM K = 39.1 g/mol
MM K2CO3 . 10H2O = 2x39.1 + 12.01 + 3 x 15.99 + 10 x 18.02= 318.38 g/mol
% by weight = (MM K/MM K2CO3.10H2O ) x 100= (39.1/318.8) x 100=12.26 %
The darn answer u nimbisol is the opposite
Answer:
408g
Explanation:
Relative atomic mass of NO: 14+16 =30
16/30*100= 53.3%(percentage by mass of O in NO)
53.3/100*765= mass of O
=408g
