Answer:
130,000 cubic centimeters
Explanation:
The volume of a box is its length multiplied by its width multiplied by its height (lwh). 423 times 12 times 25 is 126,900. When multiplying, the number of significant figures is the same as the number with the least number of significant figures. The correct number of significant figures in this example is 2, so 126,900 would need to round up to 130,000 in order to have 2 significant figures.
Answer:
This problem is providing a chemical equation between two hypothetical elements, X and Y and asks for the molesof X that are needed to
produce 21.00 moles of D in excess Y. After the following work, the answer turns out to be 15.75 mol X:Mole ratios:In chemistry, one the most crucial branches is stoichiometry, which allows us to perform calculations with grams, moles and particles (atoms, molecules and ions). It is based on the concept of mole ratios, whereby the moles of a specific substance can be converted to moles of another one, say product to reactant, reactant to reactant, reactant to product and product to product.
Calculations:In such a way, since 21.00 moles of D are given, we need the mole ratio of D to X in order to get the answer, which according to the reaction is 3:4 based on their coefficients in the reaction. Hence, we calculate the required as follows:
Explanation:
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Answer:
bleaching powder is actually a mixture of calcium chloride, calcium hydroxide and calcium hypochlorite. hence it is not a single salt. It is not completely soluble in water as it composed of heavy calcium salts, which are known to be insoluble in water.
Answer:
The molecular formula of the metal oxide is CuO
Explanation:
Molar mass 79.545 g/m belongs to CuO
This is the reaction:
2Cu(s) + O₂(g) → 2CuO (s)
2 mol of Cu produce 2 mol of CuO
Molar mass Cu = 63.5 g/m
Mass / Molar mass = 1.56 g / 63.5 g/m →0.0245 m
0.0245 mol of Cu produce 0.0245 mole of CuO
Molar mass CuO = 79.545 g/m
Mol . Molar mass = mass
0.0245 m . 79.545 g/m = 1.95 g
I have an article here that might help you understand more about villis and also aid you in answering your question:
"<span>Intestinal villi (singular: villus) are tiny, finger-like projections that come out from the wall of the small intestine and have additional extensions called microvilli (singular: microvillus) which protrude from epithelial cells lining villi. They increase the absorptive area and the surface area of the intestinal wall. It is important that the food is absorbed at a considerably fast rate so as to allow more food to be absorbed. (If the process is too slow, the concentration of the blood in the blood vessels and the food will be equal, thus, diffusion will not occur.) Digested nutrients (including sugars and amino acids) pass into the villi through diffusion. Circulating blood then carries these nutrients away. </span>
<span>In all humans, the villi and microvilli together increase intestinal absorptive surface area 30-fold and 600-fold, respectively, providing exceptionally efficient absorption of nutrients in the lumen. This increases the surface area so there are more places of food to be absorbed. </span>
<span>Villi are made up of several cells."
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