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erastova [34]
3 years ago
10

Suppose there are 2.0 x 109 microvilli per cm2 of intestinal epithelium. calculate the total surface area of the microvilli in o

ne cm2 of intestinal epithelium.
Chemistry
1 answer:
ivanzaharov [21]3 years ago
7 0
I have an article here that might help you understand more about villis and also aid you in answering your question:

"<span>Intestinal villi (singular: villus) are tiny, finger-like projections that come out from the wall of the small intestine and have additional extensions called microvilli (singular: microvillus) which protrude from epithelial cells lining villi. They increase the absorptive area and the surface area of the intestinal wall. It is important that the food is absorbed at a considerably fast rate so as to allow more food to be absorbed. (If the process is too slow, the concentration of the blood in the blood vessels and the food will be equal, thus, diffusion will not occur.) Digested nutrients (including sugars and amino acids) pass into the villi through diffusion. Circulating blood then carries these nutrients away. </span>

<span>In all humans, the villi and microvilli together increase intestinal absorptive surface area 30-fold and 600-fold, respectively, providing exceptionally efficient absorption of nutrients in the lumen. This increases the surface area so there are more places of food to be absorbed. </span>

<span>Villi are made up of several cells."

------------------------------

I hope it has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Answer is A
All elements on the periodic table have a different number of protons that can be represented by its atomic number
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Answer:

phosphorus - least similar to barium

beryllium - most similar to barium

Explanation:

The formula of the chloride formed between barium and chlorine is BaCl2.

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Phosphorus is a nonmetal and forms a completely different chloride from BaCl2. The chloride of phosphorus is PCl5 and PCl3. These are least similar to BaCl2

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A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
elena55 [62]

Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

m_{a} C_{a}  [T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

4 0
3 years ago
Balanced or Unbalanced<br><br> CH4+4Ci2=CCi4+4HCi
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balanced

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