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erastova [34]
3 years ago
10

Suppose there are 2.0 x 109 microvilli per cm2 of intestinal epithelium. calculate the total surface area of the microvilli in o

ne cm2 of intestinal epithelium.
Chemistry
1 answer:
ivanzaharov [21]3 years ago
7 0
I have an article here that might help you understand more about villis and also aid you in answering your question:

"<span>Intestinal villi (singular: villus) are tiny, finger-like projections that come out from the wall of the small intestine and have additional extensions called microvilli (singular: microvillus) which protrude from epithelial cells lining villi. They increase the absorptive area and the surface area of the intestinal wall. It is important that the food is absorbed at a considerably fast rate so as to allow more food to be absorbed. (If the process is too slow, the concentration of the blood in the blood vessels and the food will be equal, thus, diffusion will not occur.) Digested nutrients (including sugars and amino acids) pass into the villi through diffusion. Circulating blood then carries these nutrients away. </span>

<span>In all humans, the villi and microvilli together increase intestinal absorptive surface area 30-fold and 600-fold, respectively, providing exceptionally efficient absorption of nutrients in the lumen. This increases the surface area so there are more places of food to be absorbed. </span>

<span>Villi are made up of several cells."

------------------------------

I hope it has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

Regards.

6 0
3 years ago
To calculate the frequency of an electromagnetic wave, you need to know the speed of the wave which you already know as 186000 m
nirvana33 [79]
To finish calculating the frequency of an electromagnetic wave, you need the wavelength
3 0
3 years ago
Read 2 more answers
"46.7 g of water at 80.6 oC is added to a calorimeter that contains 45.33 g of water at 40.6 oC. If the final temperature of the
soldier1979 [14.2K]

<u>Answer:</u> The specific heat of calorimeter is 30.68 J/g°C

<u>Explanation:</u>

When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[(m_2\times c_2)+c_3](T_{final}-T_2)       ......(1)

where,

q = heat absorbed or released

m_1 = mass of hot water = 46.7 g

m_2 = mass of cold water = 45.33 g

T_{final} = final temperature = 59.4°C

T_1 = initial temperature of hot water = 80.6°C

T_2 = initial temperature of cold water = 40.6°C

c_1 = specific heat of hot water = 4.184 J/g°C

c_2 = specific heat of cold water = 4.184 J/g°C

c_3 = specific heat of calorimeter = ? J/g°C

Putting values in equation 1, we get:

46.7\times 4.184\times (59.4-80.6)=-[(45.33\times 4.184)+c_3](59.4-40.6)

c_3=30.68J/g^oC

Hence, the specific heat of calorimeter is 30.68 J/g°C

6 0
3 years ago
Number of moles in 1.806*10^22 molecules of nitrogen
Fynjy0 [20]
Hi there!

• Avogadro's number = 6.023 × 10²³
• No.of molecules in N = 1.806 × 10²²  [ Given ]

It's known that :-

Number of molecules = Moles × Avogadro's number

=> 1.806 × 10²² = Mol. × 6.023 × 10²³

=> Mole = \dfrac {1.806 \cdot 10^{22} }{6.023 \cdot 10^{23} }

=> Moles = 0.03 mol.

Hence, 0.03 mol. is th' required answer.

~ Hope it helps!
3 0
3 years ago
An electrochemical cell has the following standard cell notation.
Alona [7]

Explanation:

The given following standard cell notation.  

Mg(s) | Mg^2+ (aq) || Aq^+(aq) | Aq(s)

Oxidation:

Mg(s)\rightarrow Mg^{2+}+2e^-....(1)

Magnesium metal by loosing 2 electrons is getting converted into magnesium cation. Hence, getting oxidized

Reduction:

Ag^+(aq)+1e^-\rightarrow Ag(s)...(2)

Silver ion by gaining 1 electrons is getting converted into silver metal. Hence, getting reduced.

Overall redox reaction: (1)+2 × (2)

Mg(s)+2Ag^+(aq)\rightarrow Mg^{2+}+2Ag(s)

4 0
3 years ago
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