The work done on the gas during this process if the final pressure is 456 kPa is; -82.8 kJ
<h3>Workdone in Thermodynamics</h3>
We are given;
The initial pressure; P₁ = 96 kPa
Final Pressure; P₂ = 456 kPa
The gas is compressed according to;
p = aV + b
where;
a = -1200 kPa/m³
b = 600 kPa
Thus, at initial pressure P₁ = 96 kPa;
96 = -1200V₁ + 600
1200V₁ = 600 - 95
1200V₁ = 505
V₁ = 505/1200
V₁ = 0.42 m³
At Final Pressure P₂ = 456 kPa;
456 = -1200V₂ + 600
1200V₂ = 600 - 456
1200V₂ = 144
V₂ = 144/1200
V₂ = 0.12 m³
Formula for the workdone during the process is;
W_out = ¹/₂(P₁ + P₂)(V₂ - V₁)
W_out = ¹/₂(96 + 456)(0.12 - 0.42)
W_out = -82.8 kJ
Read more about workdone in thermodynamics at; brainly.com/question/12641937
Answer:
Explanation:
speed of motor (N)=1500 rpm
power=4 hp = =2.9828 KW
service factor(k)= 2.75
now,
torque rating
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
Answer:
t = 5.27 years
Explanation:
First of all, the formula for corrosion penetration rate is given as;
CPR = (KW)/(ρAt)
Where;
K = Constant dependent on exposed area A.
W - weight lost after time
t- time
ρ - density
A - exposed area
From the question;
W = 7.6kg or 7.6 x 10^(6) mg
CPR = 4 mm/yr
ρ = 4.5 g/cm³
Area = 800 cm²
K is a constant of 87.6cm
Making t the subject of the formula from the CPR equation, we obtain;
t = KW/(ρA(CPR))
t = (87.6 x 7.6 x 10^(6))/(4.5 x 800 x 4) = 46233.3 hours
The question wants the time in years.
So let's convert;
There are 8760 hours in a year.
Thus;
t = 46233.3/8760 = 5.27 years.
Answer:
To add technology and advancements to society and make out community more advanced.
Explanation: