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scZoUnD [109]
3 years ago
11

Carbon dioxide steadily flows into a constant pressure heater at 300 K and 100 kPa witha mass flow rate of 9.2 kg/s. Heat transf

er in the rate of 175 kW is supplied to the carbondioxide as it flows through the heater. Determinea) the carbon dioxide temperature at the exit andb) carbon dioxide volume flow rate at the heater exit.Assume constant specific heat, cp, of 1075 J/(kg K).

Engineering
1 answer:
docker41 [41]3 years ago
8 0

Answer:

Carbon dioxide temperature at exit is 317.69 K

Carbon dioxide flow rate at heater exit is 20.25 m³/s

Explanation:

Detailed steps are attached below.

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5 0
3 years ago
(a) Consider a message signal containing frequency components at 100, 200, and 400 Hz. This signal is applied to a SSB modulator
MakcuM [25]

Answer:

Explanation:

The frequency components in the message signal are

f1 = 100Hz, f2 = 200Hz and f3 = 400Hz

When amplitude modulated with a carrier signal of frequency fc = 100kHz

Generates the following frequency components

Lower side band

100k - 100 = 99.9kHz\\\\100k - 200 = 99.8kHz\\\\100k - 400 = 99.6kHz\\\\

Carrier frequency 100kHz

Upper side band

100k + 100 = 100.1kHz\\\\100k + 200 = 100.2kHz\\\\100k + 400 = 100.4kHz

After passing through the SSB filter that filters the lower side band, the transmitted frequency component will be

100k, 100.1k, 100.2k\ \texttt {and}\ 100.4kHz

At the receive these are mixed (superheterodyned) with local ocillator frequency whichh is 100.02KHz, the output frequencies will be

100.02 - 100.1k = 0.08k = 80Hz\\\\100.02 - 100.2k = 0.18k = 180Hz\\\\100.02 - 100.4 = 0.38k = 380Hz

After passing through the SSB filter that filters the higher side band, the transmitted frequency component will be

100k, 99.9k, 99.8k\ \ and \ \99.6kHz

At the receive these are mixed (superheterodyned) with local oscillator frequency which is 100.02KHz, and then fed to the detector whose output frequencies will be

100.02 - 99.9k = 0.12k = 120Hz\\\\100.02 - 99.8k = 0.22k = 220Hz\\\\100.02 - 99.6k = 0.42k = 420Hz

3 0
3 years ago
The water level in a tank is 20 m above the ground. A hose is connected to the bottom of the tank, and the nozzle at the end of
weeeeeb [17]

Answer:

P_{pump}= 68600Pa

Explanation:

We understand that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

In this way,

P_{tank} + P_{pump} = P_{nozzle}

For the pressure we also know that it is given by

P=\rho gh

\rho gh_1 + P_{pump} = \rho gh_2

So,

P_{pump} = \rho g(h2 - h1)

P_{pump}= 1000*9.8(27-20)

P_{pump}= 68600Pa

7 0
3 years ago
A smelter emits SO2 at a rate of 10,000 kg/day. The stack is 200 m tall and the plume rise is 100 m. The windspeed is 2 m/s at a
Olegator [25]

Answer:

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Explanation:

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5 0
3 years ago
Calculate the diameter of pneumatic cylinder to drive a mechanism. The force exerted by the mechanism is 80 N. The return force
sashaice [31]

Answer:

14.27 mm

Explanation:

Force = 80 Newton

Pressure exerted = 5 bar = 5×10⁵ Pa

Pressure exerted = Force/Area

Area = Force/Pressure

Area=\frac{80}{500000}\\\Rightarrow Area=0.00016\ m^2

Area of the cylinder=πd²/4

\Rightarrow \frac{\pi}{4}d^2=0.00016\\\Rightarrow d^2=\frac{4\times 0.00016}{\pi}\\\Rightarrow d^2=0.0002037\\\Rightarrow d=0.01427\ m

Hence diameter of cylinder 14.27 mm

5 0
3 years ago
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