Two transmission belts pass over a double-sheaved pulley that is attached to an axle supported by bearings at A and D. The radiu
s of the inner sheave is 125 mm and the radius of the outer sheave is 250 mm. Knowing that when the system is at rest, the tension is 100 N in both portions of belt B and 160 N in both portions of belt C, determine the reactions at A and D. Assume that the bearing at D does not exert any axial thrust.
1 answer:
You might be interested in
Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:
= moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
- Nitrogen gas:
molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: = 142.85mols
- Carbon Dioxide:
molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
For Nitrogen gas:
= 0.6
For Carbon Dioxide:
0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.