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Rama09 [41]
3 years ago
8

To which galaxy does the Sun belong?

Chemistry
2 answers:
hodyreva [135]3 years ago
7 0
The answer is b the Milky Way.
Alex Ar [27]3 years ago
6 0
B Milky Way :) have a good day
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How is dry ice different from ordinary ice?
True [87]

Answer: Well "ordinary ice" is made from water (as we all know) and dried ice is made from carbon dioxide gas

Explanation:

•Hope this helps•

5 0
3 years ago
More strong base is added until the equivalence point is reached. what is the ph of this solution at the equivalence point if th
Vlad [161]

A more strong base is added until the equivalence point is reached. The ph of this solution at the equivalence point if the total volume is 57. 0 mill is 9.8

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

To learn more about pH please visit -
brainly.com/question/15289741
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7 0
1 year ago
Which of the following describe chemical properties?
VLD [36.1K]
Antacid tablets neutralize stomach acid
4 0
4 years ago
The normal boiling point of bromine is 58.8°C, and its enthalpy of vaporization is 30.91 kJ/mol. What is the approximate vapor p
saul85 [17]

Answer : The vapor pressure of bromine at 10.0^oC is 0.1448 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of bromine at 10.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 10.0^oC=273+10.0=283.0K

T_2 = normal boiling point of bromine = 58.8^oC=273+58.8=331.8K

\Delta H_{vap} = heat of vaporization = 30.91 kJ/mole = 30910 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{30910J/mole}{8.314J/K.mole}\times (\frac{1}{283.0K}-\frac{1}{331.8K})

P_1=0.1448atm

Hence, the vapor pressure of bromine at 10.0^oC is 0.1448 atm.

4 0
3 years ago
What is 6421 in scientific notation
Lynna [10]
The scientific notation should specific the significant digits. So it to write like x.xx * 10 ^ x. So the answer is 6.421 * 10 ^3.
4 0
3 years ago
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