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2 years ago

HEEELP PLEASE HELP ASAP WILL AWARD BRAINLIEST What is the IUPAC name for this compound?

Chemistry

2 answers:

VladimirAG [237]2 years ago

8 0

Answer:

The Correct IUPAC name is H3C - CH (CH3) - CH (C2H5) - (CH2)2 - CH3 Class 11

Explanation:

yes searched np is maybe right i not 100% sure i 50% is it right >:) tell if u got it right >:D

ser-zykov [4K]2 years ago

4 0

Answer:

4-ethyl-6-methyl-3-heptene

Explanation:

Longest chain is seven long so it is heptane

But there is a double bond, so that becomes heptene

The double bound starts on the third carbon, so it is 3-heptene (this tells us where the double bond is)

Now we just got to do the substituents!

There is a ethyl group of the fourth carbon and then a methyl group on the sixth!

Ergo, 4-ethyl-6-methyl-3-heptene

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astraxan [27]

Answer is (4) - Pb.

According to the reactivity series of elements

- the elements which are above the hydrogen are more reactive than hydrogen.

- the elements which are below the hydrogen are less reactive than hydrogen.

Among the given choices, only Pb is placed above the hydrogen in the reactivity series and rest are below the hydrogen.

Hence, Pb is more active than hydrogen.

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3 years ago

List the objects from the smallest to the largest mass.

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2 years ago

A train travels 803.98 meters in 1 minute what is the trains average rate of speed

TEA [102]

Answer:

Approximately 13.4 meters per second (m/s)

Explanation:

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Best of Luck!

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3 years ago

In which phase of matter do the particles have the highest state of energy?

alina1380 [7]

A-plasma
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3 years ago

Read 2 more answers

Consider the chemical equations shown here.

vichka [17]

P₄0₆ $_{s}$ + 20₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$

Explanation:

The overall equation for the reaction that produces P₄0₁₀ is :

P₄0₆ $_{s}$ + 20₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$

Now let us derive this equation:

Given equations:

P₄ $_{s}$ + 30₂ $_{g}$ ⇒ P₄0₆ $_{s}$ equation 1;

P₄ $_{s}$ + 50₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$ equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

P₄0₆ $_{s}$ ⇒ P₄ $_{s}$ + 30₂ $_{g}$ equation 3

equation 2:

P₄ $_{s}$ + 50₂ $_{g}$ + P₄0₆ $_{s}$ ⇒ P₄0₁₀ $_{s}$ + P₄ $_{s}$ + 30₂ $_{g}$

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

P₄0₆ $_{s}$ + 20₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

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2 years ago