<span>The maxima of an equation can be obtained by taking the 1st
derivative of the equation then equate it to 0.</span>The value of N that result in best yield is when dy/dn = 0.
Taking the 1st derivative of
the equation y=(kn)/(9+n^2) :<span>
</span>
By using the quotient
rule the form of the equation is:<span>
y = g(n) / h(n)
where:</span>
g(n) = kn --->
g'(n) = k
<span>
<span>h(n) = 9 + n^2 ---> h'(n) = 2n </span>
dy/dn is defined as:
<span>dy/dn = [h(n) * g'(n) - h'(n) * g(n)] / h(n)^2
dy/dn = [(9 + n^2)(k) - (kn)(2n)] / (9 +
n^2)^2
dy/dn = (9k + kn^2 - 2kn^2) / (9 + n^2)^2
dy/dn = (9k - kn^2) / (9 + n^2)^2
dy/dn = k(9 - n^2) / (9 + n^2)^2
<span>Equate dy/dn = 0, then solve for n
k(9 - n^2) / (9 + n^2)^2 = 0
k(9 - n^2) = 0
9 - n^2 = 0
n^2 = 9
n = sqrt(9)
n = 3
<span>Answer: The nitrogen
level that gives the best yield of agricultural crops is 3 units.</span></span></span></span>
Static friction
hope this helps
Answer:
2.3 Nm clockwise
Explanation:
Take counterclockwise to be positive and clockwise to be negative.
∑τ = (3 N) (2.5 m) − (7 N) (1.4 m)
∑τ = 7.5 Nm − 9.8 Nm
∑τ = -2.3 Nm
The net torque is 2.3 Nm clockwise.
Force=tension-fg sin ∅
=140-mg sin 18.5
=140-124.35
=15.62N
a=f/m=15.62/40=0.39
now,
v²=u²+2as
=2×0.39×80
v²=62.4
v=7.8m/s
