Question

There are 6.022 x 10^23 atoms of Hg in 1 mole of Hg. The number of atoms in 4.5 moles of Hg can be found by multiplying 4.5 by 6.022 x 10^23
A. 2.7 x 10^24
B. 27 x 10^23
C. 2.71 x10^24
D. 27.099 x 10^23

Answer 1

Answer: $27\times 10^{23}$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of $Hg$ contains = $6.023\times 10^{23}$ atoms of mercury

Thus 4.5 moles of $Hg$ contains = $\frac{6.023\times 10^{23}}{1}\times 4.5=27.099\times 10^{23}$ atoms of mercury

Thus the number of atoms in 4.5 moles of mercury are $27\times 10^{23}$ atoms of mercury.

Answer 2

Answer:

D. 27.099 x 10²³.

Explanation:

• It is known that every 1.0 mole of an atom contains Avogadro's no. (6.022 x 10²³) atoms.

So, 4.5 mol of Hg will contain:

(4.5 mol)(6.022 x 10²³) = 27.099 x 10²³ atoms.

So, the right choice is: D. 27.099 x 10²³.