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oksano4ka [1.4K]
3 years ago
6

Oh somebody please do help me

Mathematics
2 answers:
Nana76 [90]3 years ago
7 0

Answer:

Bacteria

Step-by-step explanation:

Bacteria dominate the early process in compost and probably will make up 80 to 90 % of compost microbes. Most bacteria found in soils and in compost are decomposers. A teaspoon of fertile soil can contain anywhere from 100 million to a billion bacteria with representatives from 10,000 species.

MArishka [77]3 years ago
5 0
D. Bacteria because trees
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42 is 60% of 70, find this answer by dividing 42 by 70
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Which idea from the text is too detailed to include in a summary of the text?
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It includes specifics which shouldn’t be in a summary

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An Austrian study was completed to determine if untrained sea lions and sea lionesses could follow various experimenter-given cu
Sholpan [36]

Using the z-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

<h3>What are the hypothesis?</h3>
  • At the null hypothesis, it is tested if Zwerg cannot correctly follow this type of direction by an experimenter more than 50% of the time, that is:

H_0: p \leq 0.5

  • At the alternative hypothesis, it is tested if Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time, that is:

H_1: p > 0.5

<h3>Test statistic</h3>

The <em>test statistic</em> is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are:

n = 48, \overline{p} = \frac{37}{48} = 0.7708, p = 0.5

The value of the <em>test statistic</em> is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.7708 - 0.5}{\sqrt{\frac{0.5(0.5)}{48}}}

z = 3.75

Considering a <u>right-tailed test</u>, as we are testing if the proportion is greater than a value, with a <u>significance level of 0.05</u>, the critical value for the z-distribution is z^{\ast} = 1.645.

Since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

To learn more about the z-distribution, you can take a look at brainly.com/question/16313918

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3 years ago
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-10y

Step-by-step explanation:

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4 years ago
Kim purchases pet insurance for her cat. In 2011 , she paid $40 per month. She switched to discount insurance she bought online
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The discount = 40 - 34 = 6 
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