Answer:
The solution is 
. Fourth option
Explanation:
Solve for x:
Move all the terms from the right to the left side of the equation, a zero in the right side:
Join all like terms:
The general form of the quadratic equation is:
Solve the quadratic equation by using the formula:
In our equation: a=1, b=-2, c=-46
Substituting into the formula:
Since 188=4*47
Take the square root of 4:
Divide by 2:
First option: Incorrect. The answer does not match
Second option: Incorrect. The answer does not match
Third option: Incorrect. The answer does not match
Fourth option: Correct. The answer matches exactly this option
There would be about a 14.3% chance of being able to see it
30 minutes / 210
.1428 =
14.3%
Answer:
i can;t copy or paste either bro
Step-by-step explanation:
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
