Answer:
L = 4.711 *10^{-6} kg m2/s
Explanation:
=4.5*10^-5
angular velocity
= 0.1047 rad/s
the angular momentum,
Answer:
d. The length of the string is equal to one-half of a wavelength.
Explanation:
For a standing waves vibrating with Fundamental Frequency will be vibrate in one loop so Length 2 L = λ ⇒ L = 1/2 λ
It becomes faster because there is less weight being pulled
For vertical motion, use the following kinematics equation:
H(t) = X + Vt + 0.5At²
H(t) is the height of the ball at any point in time t for t ≥ 0s
X is the initial height
V is the initial vertical velocity
A is the constant vertical acceleration
Given values:
X = 1.4m
V = 0m/s (starting from free fall)
A = -9.81m/s² (downward acceleration due to gravity near the earth's surface)
Plug in these values to get H(t):
H(t) = 1.4 + 0t - 4.905t²
H(t) = 1.4 - 4.905t²
We want to calculate when the ball hits the ground, i.e. find a time t when H(t) = 0m, so let us substitute H(t) = 0 into the equation and solve for t:
1.4 - 4.905t² = 0
4.905t² = 1.4
t² = 0.2854
t = ±0.5342s
Reject t = -0.5342s because this doesn't make sense within the context of the problem (we only let t ≥ 0s for the ball's motion H(t))
t = 0.53s
Ans:
12500 N/C
Explanation:
Side of square, a = 2.42 m
q = 4.25 x 10^-6 C
The formula for the electric field is given by
where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges
According to the diagram
BD =
where, a be the side of the square
So, Electric field at B due to charge at A
EA = 6531.32 N/C
Electric field at B due to charge at C
Ec = 6531.32 N/C
Electric field at B due to charge at D
ED = 3265.66 N/C
Now resolve the components along X axis and Y axis
Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C
Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C
The resultant electric field at B is given by
E = 12500 N/C
Explanation: