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allsm [11]
3 years ago
6

Another engineer is running a series of experiments with hydraulic systems. If she doubles the area of the input piston, what ha

ppens to the amount of pressure transmitted by the system?
Physics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

The pressure remains the same.

F = P * A  the amount of force transmitted would double if only the input area is changed. Pressure is the same at all points in the system.

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PLEASE HELP!
Anna [14]

Answer:

Explanation:

At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume

ΔV = 9.2 - 5.6 = 3.6 L

3.6 L = 3.6 x 10⁻³ m³

ΔV = 3.6 x 10⁻³ m³

P = 3.7 x 10³ Pa

So work done

= 3.7 x 10³ x 3.6 x 10⁻³ J

= 13.32 J .

( c ) is the answer , because work is done by the gas so it will be positive.

5 0
3 years ago
Read 2 more answers
Which of the following expressions for power or dimensionally correct?
Slav-nsk [51]

Power=F.V

dimension: ML^2T^-2


8 0
3 years ago
A particular radio station broadcast radio waves at 100 MHz (100 million Hz). If the radio waves travel at the speed of light (3
Svetlanka [38]


Wavelength  =  (speed) / (frequency)


                      =  (3 x 10⁸ m/s) / (1 x 10⁸ /s)  =  3 meters 

4 0
3 years ago
A bowling ball with a negative initial velocity slows down as it rolls down the lane toward the pins. Is the bowling ballâs acce
stiv31 [10]

Answer:

positive

Explanation:

The ball is rolling down with a negative velocity, but the velocity is slowing down. therefore the velocity must increase in order for the ball to slow down.

For example let the ball's initial velocity be -15 m/s. and it  is slowing down to let's say -13 m/s. Well this means that it's velocity has increase by 2 m/s. So, its acceleration is positive.

5 0
3 years ago
a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall
RUDIKE [14]
The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.

The putty and the ball have the same mass, and you throw them
with the same speed.  So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
    Its momentum changed by an amount of  M .

-- The ball has momentum of " M in the direction away from the wall ".
    Its momentum changed by an amount of  2M .
5 0
4 years ago
Read 2 more answers
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