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allsm [11]
3 years ago
6

Another engineer is running a series of experiments with hydraulic systems. If she doubles the area of the input piston, what ha

ppens to the amount of pressure transmitted by the system?
Physics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

The pressure remains the same.

F = P * A  the amount of force transmitted would double if only the input area is changed. Pressure is the same at all points in the system.

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A sports car traveling along a straight line increases its speed from 19.8 mi/h to 59.9 mi/h.a. What is the ratio of the final t
Natasha2012 [34]

Answer

given,

initial speed of the car (v₁)= 19.8 mi/h

final speed of the car (v₂)= 59.9 mi/h

a) initial momentum = m v₁

                   P₁ = 19.8 m

  final final momentum = m v₂

                   P₂ = 59.9 m

      ratio = \dfrac{P_2}{P_1}

              =\dfrac{59.9 m}{19.8 m}

      ratio of momentum=\dfrac{P_2}{P_1}=3.025

b) initial kinetic energy= 1/2 m v₁²

                   K₁ = 196.02 m

  final kinetic energy= 1/2 m v₂²

                   K₂ = 1794.005 m

      ratio = \dfrac{K_2}{K_1}

              =\dfrac{1794.005 m}{196.02 m}

      ratio of Kinetic energy=\dfrac{P_2}{P_1}=9.15

8 0
3 years ago
An eartly method of measuring the speed of light makes use of a rotating slotted wheel.
Pavel [41]

Answer:

Explanation:

Distance traveled by light = 2 x 550 m = 1100 m

time taken by light to travel this distance = 1100 / 3 x 10⁸

=  366.67 x 10⁻⁸ s

angle between two consecutive slots = 2π / 500 rad

= .004π

angular velocity of wheel = angle moved / time taken

= .004π / 366.67 x 10⁻⁸

= 1091π radian / s

b )  linear speed of a point on the edge of the wheel

= ω R , r is radius of wheel , ω is angular velocity.

= 1091π x 5 x 10⁻²

= 1712.8 m /s

4 0
4 years ago
An asteroid has a radius of 110,000 m
nydimaria [60]

Answer: M = 6.13 × 10^18 kg

Explanation:

g = GM/r2,

Where

The mass M of the asteroid = ?

The radius r = 110000 m

g = 0.0338 m/s^2

G is the gravitational constant.

SI units its value is approximately 6.674×10^−11m3⋅kg−1⋅s−2

Using the formula

g = GM/r2

Cross multiply

GM = gr^2

6.674×10^-11M = 0.0338 × 110000^2

M = 408×10^6/6.674×10^-11

M = 6.13 × 10^18 kg

7 0
4 years ago
The Bohr model pictures a hydrogen atom in its ground state as a proton and an electron separated by the distance a0 = 0.529 × 1
Tpy6a [65]

Answer:

E = -8.23 ​​10⁻¹⁷ N / C

Explanation:

In the Bohr model, the electric potential for the ground state corresponding to the Bohr orbit is

         E = k q₁ q₂ / r²

in this case

q₁ is the charge of the proton and q₂ the charge of the electron

         E = - k e² / a₀²

let's calculate

         E = - 9 10⁹ (1.6 10⁻¹⁹)² / (0.529 10⁻¹⁰)²

         E = -8.23 ​​10⁻¹⁷ N / C

8 0
3 years ago
4. Which of the following would be a good reference point to describe the motion of a dog?
saul85 [17]

ANOTHER RUNNING DOG

Explanation:

In the given question it is to find a suitable reference point to describe  the motion of dog. Here I could suggest that it is better to compare the dog with  another running dog to create the relative speed difference to get a reliable motion variation.

Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to  another dog which is already in motion.

Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with  another dog running.

4 0
3 years ago
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