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OleMash [197]
3 years ago
12

Plz answer very easy question

Chemistry
1 answer:
Vinvika [58]3 years ago
7 0
A: they all have protons
b:they have a different amount of neutrons
c:protons neutrons and electrons
d: the atom itself would change
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1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol
AnnyKZ [126]
<span>1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol
The independent variable would be ethylene glycol and dependent variable would be density.

A. A 25-mL volumetric flask with its stopper has a mass of 32.6341 g. The same flask filled to the line with ethylene glycol (C2H6O2, automotive antifreeze) solution has a mass of 58.0091 g. What is the density of the ethylene glycol solution?

Density = 58.0091 - 32.6341 / .025 = 1015 g/L

B. What is the molarity of the ethylene glycol solution, if the mass of ethylene glycol in the solution is 12.0439 g?

Molarity = 12.0439 ( 1 mol / 62.07 g) / 0.025 = 7.8 M</span>
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3 years ago
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What is an energy source produced from nuclear reactions
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I believe it would be electricity.

Explanation:

6 0
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Look at the diagram. What number needs to be added to balance the equation?
suter [353]

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2

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Write the following formulas in words:<br> a. НСІ<br> b. Naci
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8 0
3 years ago
If a laser light is compose of photons each with an energy of 4.58 × 10−19 J, what is the photon energy of this light in units o
kap26 [50]

Answer : The photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

Solution :

Formula used :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = 4.58\times 10^{-19}J

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Now put all the given values in the above formula, we get:

4.58\times 10^{-19}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}

\lambda=4.3017\times 10^{-7}m=434.017\times 10^{-9}m=434.017nm=4.34\times 10^{-2}nm

conversion used : (1nm=1\times 10^{-9}m)

Therefore, the photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

5 0
3 years ago
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