To get the concentration of the second solution let us use the following formulae
C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.
therefore
0.8×2=(2+10)×C2
1.6 =12×C2
1.6/12=C2
C2 = 0.1333mg/mL
Answer:
clf3
Explanation:
it occupied more than 8 valence electrons
Molar mass Na = 23g/mol
46g = 456/2 = 2mol
1mol = 6.022*10^23 atoms
2mol = 2*6.022*10623
= 1.204*10^24 atoms
It should be noted that bond A has greater energy because C. The atoms in bond A are held more tightly together than the atoms in bond B.
<h3>Bond</h3>
The relationship between the bond energies of nitrogen, iodine, and fluorine gases is that the bond in nitrogen gas is the most difficult to break.
From the information given, the molecule with the greatest bid energy is CH4. The bind energy measures the bond strength that the chemical bond has.
Also, the bond energy of the reactants in reaction 1 is greater than the bond energy of the reactants in reaction 2. Due to this, reaction 1 requires a greater input of energy than reaction 2.
Lastly, the difference in the bond energy of Chlorine and Bromine is that Bromine has more electron levels than chlorine.
Learn more about bonds on:
brainly.com/question/819068
Answer: A. 4sf B.2sf C.6sf D.1sf E.4sf
Hope this helps! :)
