Answer:
Explanation: So 1 Kelvin is equal to -272.15 Celsius. Now we need to do some math,
563,180 x -272.15 = -153,269,437 Celsius
I hope this helps :)
The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O
We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:
How to determine the mass of C
- Mass of CO₂ = 9.78 g
- Molar mass of CO₂ = 44 g/mol
- Molar of C = 12 g/mol
- Mass of C =?
Mass of C = (12 / 44) × 9.78
Mass of C = 2.67 g
How to determine the mass of H
- Mass of H₂O = 20.99 g
- Molar mass of H₂O = 18 g/mol
- Molar of H = 2 × 1 = 2 g/mol
- Mass of H =?
Mass of H = (2 / 18) × 4
Mass of H = 0.44 g
How to determine the mass of O
- Mass of compound = 4.30 g
- Mass of C = 2.67 g
- Mass of H = 0.44 g
- Mass of O =?
Mass of O = (mass of compound) – (mass of C + mass of H)
Mass of O = 4.30 – (2.67 + 0.44)
Mass of O = 1.19 g
<h3>How to determine the empirical formula </h3>
The empirical formula of the compound can be obtained as follow:
- C = 2.67 g
- H = 0.44 g
- O = 1.19 g
- Empirical formula =?
Divide by their molar mass
C = 2.67 / 12 = 0.2225
H = 0.44 / 1 = 0.44
O = 1.19 / 16 = 0.074
Divide by the smallest
C = 0.2225 / 0.074 = 3
H = 0.44 / 0.0744 = 6
O = 0.074 / 0.074 = 1
Thus, the empirical formula of the compound is C₃H₆O
Learn more about empirical formula:
brainly.com/question/9459553
#SPJ1
True due to the fact that eight electrons are what applies directly to the octet rule
1. Q=112.8 kJ
2. Q=5.01 kJ
<h3>Further explanation</h3>
The heat required for phase change :
Q = mLf
Lf=latent heat of fusion
- vaporization/condensation
Q = mLv
Lv=latent heat of vaporization
1.
m=50 g=0.05 kg
Lv (water) = 2256 kJ/kg
2.
m=15 g=0.015 kg
Lf for water = 334 kj/kg
about the door is locked and I think I have a few questions about the door is locked and I think I have
Explanation:
can you tell me what the door is locked and I think I have a few questions about the door is locked and I think I have a few questions
