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docker41 [41]
3 years ago
6

Explain why open pipes are preferred to closed pipe in the production of music-​

Physics
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

The frequencies of sounds made by these two types of instruments are different because of the different ways that air will move at a closed or open end of the pipe. Open pipes do not produce superior tone than closed (or stopped) pipes, therefore different types of pipes are used to produce different tonal qualities.

Explanation:

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One end of the inclined plane is always higher than the other​
Charra [1.4K]

Answer:

yes then what did you want to learn

5 0
3 years ago
James decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jame
Kaylis [27]
B 1 mile/15 minutes is the right one
3 0
3 years ago
Early one February morning you go outside to build a snow man. You make a 3.2kg snowball and lift it to a height of 1.2m, then c
Verdich [7]

First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

Therefore mass× gravitational pull×height will give us the work done

=3.2kg ×9.8N/kg×1.2m

=37.632J

then, the work done over the 25m distance if found by the following formula: work done=force×distance

=1.0N×25m

=25J

On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.

therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m

=m×g×h

=3.2kg×9.8N/kg×1.1m

=34.496J

To get the total we add the amount of work done in the various instances.

4 0
4 years ago
Read 2 more answers
A force of 570 N keeps a certain ideal spring stretched a distance of 0.900 m.
Kaylis [27]

Hooke's law states that the elongation of a material is proportional to the applied stress within the elastic limits of the material.

Using Hooke's law

F = kx

570 = k * 0.9

k = 712.5 N/m

(a) energy at x = 0.8 m

U = 0.5 k x^2 = 0.5* 712.8* 0.8^2

U = 228 J

(b) U = 0.5 * 712.8* 0.09^2

U = 2.887 J

Elastic potential energy is the potential energy released as a result of the deformation of an elastic body. B. Spring extension is stored. This is equal to the work done to stretch the spring, which depends on the spring constant k and the stretched distance. The force exerted by the spring is the restoring force that helps return the spring to its equilibrium length.

Learn more about Potential energy here:- brainly.com/question/14427111

#SPJ4

3 0
1 year ago
When the hydraulic conductivity Ks = 10 mm/hr; effective matrix potential Ns = 20 mm, and rainfall intensity I = 30 mm/hr , dete
Maslowich

Answer:

t =  0.75 \ hr  =  0.75 *60  =  45 \ minutes

Explanation:

From the question we are told that

   The  hydraulic conductivity is  Ks =  10\ mm/hr

    The  effective matrix potential Ns  =  20 \ mm

    The  intensity of  rainfall is  I  =  30 \ mm/hr

    The runoff rate R =  15 \  mm/hr

Generally the run off rate is mathematically represented as  

      R = (I - Ks) t

Here t is the amount of runoff generated

=>   15 = (30 - 10) t

=>  t  =  0.75 \ hr

converting to minutes

    t =  0.75 \ hr  =  0.75 *60  =  45 \ minutes

3 0
3 years ago
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