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algol13
3 years ago
7

D= ((vf+vi)/2) t Solve for vi

Physics
2 answers:
erastovalidia [21]3 years ago
8 0
= t(Vf + Vi/2) 
<span>Vf + Vi/2 = d/t </span>
<span>Vf = (d/t) - Vi/2 </span>

<span>Answer: Vf = (d/t) - Vi/2 OR (2dt - Vit)/2t

</span>
vlada-n [284]3 years ago
7 0
D= ((vf+vi)/2) t

D = (vf +vi)*t/2

2*D = (vf +vi)*t

2D/t = vf +vi

vf +vi =  2D/t

vi = 2D/t - vf
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Please answer this question I have uploaded the picture of question please answer​
8090 [49]

Answer:

20 mangintiude beacuse

Explanation:

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5 0
3 years ago
If the radius of the sun is 7.001×105 km, what is the average density of the sun in units of grams per cubic centimeter? The vol
xenn [34]

Answer:

Average density of Sun is 1.3927 \frac{g}{cm}.

Given:

Radius of Sun = 7.001 ×10^{5} km = 7.001 ×10^{10} cm

Mass of Sun = 2 × 10^{30} kg = 2 × 10^{33} g

To find:

Average density of Sun = ?

Formula used:

Density of Sun = \frac{Mass of Sun}{Volume of Sun}

Solution:

Density of Sun is given by,

Density of Sun = \frac{Mass of Sun}{Volume of Sun}

Volume of Sun = \frac{4}{3} \pi r^{3}

Volume of Sun = \frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}

Volume of Sun = 1.436 × 10^{33} cm^{3}

Density of Sun = \frac{ 2\times 10^{33} }{1.436 \times 10^{33} }

Density of Sun = 1.3927 \frac{g}{cm}

Thus, Average density of Sun is 1.3927 \frac{g}{cm}.

4 0
3 years ago
child mass 25kg moves with speed of 1.5m/s when 7.8 from the central of merry-go round. calculate the centripetal acceleration o
MAVERICK [17]

Answer:

0.2885 m/s²

Explanation:

The formula for centripetal acceleration is given as;

a_c=v^2/r

Given that;

speed = v = 1.5m/s

radius = r = 7.8

a_c=v^2/r\\\\\\a_c=1.5^2/7.8\\\\\\a_c=0.2885m/s^{2}

8 0
3 years ago
Which of the following represents the wavelength of a wave?
dlinn [17]

Answer: D. the distance between the highest points of consecutive waves

Explanation:

The wavelength of a wave is defined as the <em>distance traveled by a periodic perturbation that propagates through a medium in a given time interval</em>. It is usually represented by \lambda and can be calculated if the frequency of the wave is known, since there is an inverse relationship between both.

In the specific case of a periodic sine wave (which is the way in which a wave is usually represented graphically) the wavelength can be determined as the distance between two consecutive maxima of the disturbance.

Therefore, the correct option is D.

8 0
3 years ago
Read 2 more answers
A Boeing 737 airliner has a mass of 20,000 kg and the total area of both wings (top or bottom) is 100 m2. What is the pressure d
kvv77 [185]

Answer:

The correct option is A = 1960 N/m²

Explanation:

Given that,

Mass m= 20,000kg

Area A = 100m²

Pressure different between top and bottom

Assume the plane has reached a cruising altitude and is not changing elevation. Then sum the forces in the vertical direction is given as

∑Fy = Wp + FL = 0

where

Wp = is the weight of the plane, and

FL is the lift pushing up on the plane.

Let solve for FL since the mass of the plane is given:

Wp + FL = 0

FL = -Wp

FL = -mg

FL = -20,000× -9.81

FL = 196,200N

FL should be positive since it is opposing the weight of the plane.

Let Equate FL to the pressure differential multiplied by the area of the wings:

FL = (Pb −Pt)⋅A

where Pb and Pt are the static pressures on bottom and top of the wings, respectively

FL = ∆P • A

∆P = FL/A

∆P = 196,200 / 100

∆P = 1962 N/m²

∆P ≈ 1960 N/m²

The pressure difference between the top and bottom surface of each wing when the airplane is in flight at a constant altitude is approximately 1960 N/m². Option A is correct

5 0
3 years ago
Read 2 more answers
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