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GalinKa [24]
2 years ago
10

C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F. Calculate the equivalent capacitance

Physics
1 answer:
grin007 [14]2 years ago
6 0

The equivalent capacitance between A and B points is 2.5F.

<h3>What is parallel plate capacitor?</h3>

The two parallel plates placed at a distance apart used to store charge when electric supply is on.

The capacitance of a capacitor is given by

C = ε₀ A/d

From the given circuit C1, C2 and C3, C4 are in parallel  C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F

C1, C2 = 4 +4 =8F

C3, C4 = 2 +4 =6F

Now , all capacitors are in series.

Total equivalent capacitance is
1 / Ceq = 1/ 8 +1/6 +1/ 9.2

Ceq = 2.5 F

Thus,  the equivalent capacitance between A and B points is 2.5F.

Learn more about parallel plate capacitor.

brainly.com/question/12733413

#SPJ1

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Answer:

In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).

Explanation:

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3 years ago
An AC source operating at a frequency of 250 Hz has a maximum output voltage of 6.00 V. What is the smallest inductor that can b
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Answer:

1.274 H

Explanation:

using

V = XLI...................Equation 1

Where V = voltage, XL = Inductive reactance, I = current.

Make XL the subject of the equation

XL = V/I.............. Equation 2

Given: V = 6.00 V, I = 3.00 mA = 0.003 A

Substitute into equation 2

XL = 6/0.003

XL = 2000 Ω

But,

XL = 2πFL............... Equation 3

Where F = Frequency, L = inductance.

Make L the subject of the equation

L = XL/(2πF).............. Equation 4

Given: F = 250 Hz, XL = 2000 Ω

Constant: π = 3.14

L = 2000/(2×3.14×250)

L = 2000/1570

L = 1.274 H.

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Explain what makes rhombus different from other quadrilaterals
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The critical difference is the fact that all four sides of a rhombus have
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There are several other distinguishing characteristics, but if you make the
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6 0
3 years ago
A 5.50 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en
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Answer:

Explanation:

position

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v(t) = 2.80 + 1.83t²

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F = ma = 5.50(3.66(4.10)) = 82.533 N

which should be rounded to no more than three significant digits and arguably only two due to the 0.61 factor.

F = 82.5 N or 83 N

Yes the units are Newtons, cannot tell what your system will accept. May not want the units at all.

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