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Dmitrij [34]
3 years ago
15

Solve the equation log(base 2) x-1/2log(base 2)(x + 1) = 1

Mathematics
1 answer:
Fantom [35]3 years ago
6 0
Use the quotient property of logarithms,
log
b
(
x
)
−
log
b
(
y
)
=
log
b
(
x
y
)
log
b
(
x
)
-
log
b
(
y
)
=
log
b
(
x
y
)
.
log
2
(
x
+
2
x
−
5
)
=
3
log
2
(
x
+
2
x
-
5
)
=
3
Rewrite
log
2
(
x
+
2
x
−
5
)
=
3
log
2
(
x
+
2
x
-
5
)
=
3
in exponential form using the definition of a logarithm. If
x
x
and
b
b
are positive real numbers and
b
b
≠
≠
1
1
, then
log
b
(
x
)
=
y
log
b
(
x
)
=
y
is equivalent to
b
y
=
x
b
y
=
x
.
2
3
=
x
+
2
x
−
5
2
3
=
x
+
2
x
-
5
Solve for
x
x
Tap for more steps...
x
=
6
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vampirchik [111]

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See attachment for graph

<em></em>

Step-by-step explanation:

Given

f(x) = \left[\begin{array}{cc}-1&x1\end{array}\right

Required

The graph of the step function

Before plotting the graph, it should be noted that:

\le and \ge use closed circle at its end

and > use open circle at its end

So, we have:

f(x) = -1,\ \ \ \ x < -1

The line stops at -1 with an open circle      

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The options are not complete, so I will plot the graph myself.

<em>See attachment for graph</em>

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