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Luda [366]
3 years ago
7

During a Buckeye football game, the quarterback throws a ‘long bomb' to a wide receiver. During it's flight, the ball reached a

maximum height of 15 m [U] before it started falling back down, and during this time flew 30m [E], where it was caught. The receiver then ran it another 15 m [E] for a touchdown. A) Determine the distance and displacement experienced in the up-down dimension by the ball b) Determine the distance and displacement experienced by the ball in the east-west dimension.
Physics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

A) The distance traveled by the ball in the Up-down dimension is 30 m

The displacement of the ball in the up-down direction is 0 m

B) The distance the ball travels in the east west direction is 45 m [East]

The displacement of the ball is the east-west direction is 45 m [East]

Explanation:

The long measures of the ball motion are;

The maximum height reached = 15 m Up

The horizontal distance traveled by the ball during flight = 30 m East

The distance the receiver ran  with the ball after the ball was caught = 15 m East

A) The distance traveled by the ball in the Up-down dimension = 15 m up + 15 m backdown = 30 m in the up-down direction

The displacement of the ball in the up-down direction, d = 15 m + (-15 m) = 0 m

B) The distance the ball travels in the east west direction = 30 m [E] + 15 m [E] = 45 [E]

The displacement of the ball is the east-west direction, d = 30 m + 15 m = 45 m [E].

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Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

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2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

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4 years ago
At divergent boundaries, hot mantle rock rises and _____ occurs.
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3 years ago
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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 j electrical energy is
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Here is the energy that is left after the quantity of energy is transformed: 750 j of electrical energy is changed into 400 j of kinetic or mechanical energy, which is then turned into 0.32 j of efficient energy.

To run the fan, electrical energy is utilized.

Here, under the specified circumstances, 750 J of electrical energy is utilized to operate the fan, which is transformed into 400 J of kinetic energy. As a result, 350 J of energy is wasted due to various frictional and resistive losses.

Therefore, we may conclude that only 400 J of the 750 J available energy is used to power the fan, with the remaining energy being wasted as a result of friction.

Additionally, we can state that this fan's effectiveness will be

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3 0
3 years ago
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Sati [7]

Answer:

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Explanation:

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