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Katen [24]
3 years ago
14

Please help me with this question:)

Physics
1 answer:
beks73 [17]3 years ago
4 0

Answer:

B

Explanation:

The more negative the colder the higher the celcius the hotter it is

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Automobile engines AND steam engines are examples of ______. a. internal combustion engines b. heat engines c. external combusti
uranmaximum [27]

Answer: B. Heat engines

Explanation:

8 0
3 years ago
Read 2 more answers
A light bulb in a camper’s flashlight is labeled 4.1 V, 0.40 A. Find the equivalent current if three of these light bulbs are co
Gnesinka [82]

Explanation:

first rule of parallel circuits : the voltage is the same in the whole circuit, no matter where we measure.

so, we have 1.5V at every bulb.

second rule of parallel circuits : the total current is the sum of the individual branch currents.

so, if the battery really allows it, then we have 3 times 0.4 A = 3×0.4 = 1.2 A as current in the circuit.

5 0
2 years ago
A 140 g air-track glider is attached to a spring. The glider is pushed in 8.2 cm against the spring, then released. A student wi
max2010maxim [7]

Answer:

Explanation:

The period of oscillation is given as

T=2π√m/k

Making k subject of the formula

Square both sides of the equation

T²=4π²(m/k)

Cross multiply

T²k=4π²m

Then, divide through by T²

k=4π²m/T²

Where

k is spring constant

m is the mass of the bob

And T is the period of the oscillation

m=140g=0.14kg

14 oscillations takes 14 seconds

Then the period is

T=time/oscillation

T=14/14

T=1sec

Then,

k=4π²m/T²

k=4π²×0.14/1²

k=1.76N/m

Then, the spring constant is 1.76N/m

4 0
4 years ago
An airplane starts at a stand-still and speeds up with an acceleration of 9.0 m/s2. If the runway is 102 m long, how long will i
Keith_Richards [23]

The plane takes 4.76 s to reach the end of the runway

Explanation:

The motion of the airplane is a uniformly accelerated motion (=at constant acceleration), therefore we can solve the problem by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time elapsed

a is the acceleration

In this problem, we have:

s = 102 m is the lenght of the runway

u = 0 is the initial velocity of the airplane

a=9.0 m/s^2 is its acceleration

Solving for t, we find the time needed to reach the end of the runway:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(102)}{9.0}}=4.76 s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
You throw a rock straight up from the edge of a cliff. It leaves your hand at time t = 0 moving at 13.0 m/s. Air resistance can
Zarrin [17]

Answer:

0.36s, 2.3s

Explanation:

Let gravitational acceleration g = 9.81 m/s2. And let the throwing point as the ground 0 for the upward motion. The equation of motion for the rock leaving your hand can be written as the following:

s = v_0t + gt^2/2

where s = 4 m is the position at 4m above your hand. v_0 = 13 m/s is the initial speed of the rock when it leaves your hand. g = -9.81m/s2 is the deceleration because it's in the downward direction. And t it the time(s) it take to get to 4m, which we are looking for

4 = 13t - 9.81t^2/2

4.905 t^2 - 13t + 4 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{13\pm \sqrt{(-13)^2 - 4*(4.905)*(4)}}{2*(4.905)}

t= \frac{13\pm9.51}{9.81}

t = 2.3 or t = 0.36

7 0
4 years ago
Read 2 more answers
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