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3 years ago

14

Please help me with this question:)

1 answer:

beks73 [17]3 years ago

4 0

Answer:

B

Explanation:

The more negative the colder the higher the celcius the hotter it is

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The following time dependent force is applied to a 2 kg block that is initially at rest on a frictionless and horizontal surface

DerKrebs [107]

Answer:

The displacement of the block is 9 m.

Explanation:

Given that,

Mass of block = 2 kg

Time = 3 sec

The force is

$F(t)=4t$

The acceleration is

$a=\dfrac{F}{m}$

Put the value into the formula

$a=\dfrac{4t}{2}$

$a=2t$

We need to calculate the velocity

Using formula of acceleration

$v=\int_{0}^{t}{a dt}$

Put the value into the formula

$v=\int_{0}^{3}(2t dt)$

$v=(\dfrac{2t^2}{2})_{0}^{3}$

$v=(t^2)_{0}^{3}$

$v=9\ m/s$

We need to calculate the displacement

Using formula of velocity

$s=\int_{0}^{3}(v dt)$

$s=(t^2)_{0}^{3}$

$s=(\dfrac{t^3}{3})_{0}^{3}$

$s=9\ m/s$

Hence, The displacement of the block is 9 m.

8 0

3 years ago

Read 2 more answers

A roller-coaster car has a mass of 1040 kg when fully loaded with passengers. As the car passes over the top of a circular hill

rusak2 [61]

Answer:

a.6373.5 N

b.-3837.6 N

Explanation:

Mass of roller coaster=m=1040 kg

Radius=r=24 ,

a. $v=9.4m/s$

Normal force= $F_N$

According to question

$mg-F_N=\frac{mv^2}{r}$

Where $g=9.81 m/s^2$

Substitute the values

$1040\times 9.81-F_N=\frac{1040\times (9.4)^2}{24}$

$10202.4-F_N=3828.9$

$F_N=10202.4-3828.9=6373.5 N$

b. $v=18m/s$

$g=9.81 m/s^2$

$1040\times 9.81-F_N=\frac{1040\times (18)^2}{24}$

$10202.4-F_N=14040$

$F_N=10202.4-14040=-3837.6 N$

8 0

4 years ago

A satellite is in a circular Earth orbit of radius r. The area A enclosed by the orbit depends on r2 because A = πr2. Determine

Salsk061 [2.6K]

Answer:

a. $T=r^{3/2}$

b. $K=\frac{1}{r}$

c. $v=\frac{1}{\sqrt{r}}$

d. $v=\sqrt{r}$

Explanation:

To make analysis about the satellite circular earth the depends or r and A

$T^2=\frac{4\pi}{GM}*r^3$

$K=\frac{GM*m}{2*r}$

a.

$T^2=r^3$

$T=r^{3/2}$

b.

$K=\frac{GM*m}{2}*\frac{1}{r}$

$K=\frac{1}{r}$

c.

$K=\frac{1}{2}*m*v^2$

$v^2=\frac{2*K}{m}=\frac{2*Gm*m}{2*m*r}$

$v=\frac{1}{\sqrt{r}}$

d.

$v=\sqrt{2*GMr}$

$v=\sqrt{r}$

3 0

3 years ago

The diagram shows two dodgeballs colliding. The red arrow shows the direction of force of the moving ball striking a stationary

Helen [10]

Answer:

The second arrow from the top to the bottom

Explanation:

This can be explained by the Newton's third law.

For every action there is an equal and opposite reaction.

When an object A exert a force to an object B. Then object B also excerts a force with the same size but opposite direction to object A.

5 0

4 years ago

Read 2 more answers

_____ are composed of ionized gas trapped in a magnetic arch rising above the surface of the Sun. When seen along the edge of th

ivanzaharov [21]

Answer:

Prominences

Explanation:

Their arched shapes show that they are formed of ionized gas trapped in the magnetic field. You see prominences in filtergrams as dark filaments silhouetted against the bright chromosphere.

7 0

3 years ago