Answer:
Mass of C = 47.37g
Mass of H = 10.59g
Mass of O = 42.04g
The total mass of these elements is 100g, taking a proportion of their molar masses.
C = 47.37/12= 3.95
H = 10.59/1 = 10.59
O = 42.04/16= 2.63.
Dividing through with the smallest proportion which is 2.63
C=3.95/2.63 = 1.5
H =10.59/2.63 =4
O = 2.63/2.63= 1
Multiplying through by 2 to get a whole number.
C = 1.5x2 = 3
H= 4x2 = 8
O = 1x2= 2
The empirical formula is C3H6O2
(Empirical formula)n= molecular mass
(C3H8O2)n =228.276
(12x3 +8+16x2)n= 228.276
76n = 228.276
n = 228.276/76
n = 3
Molecular formula = Empirical formula
=(C3H8O2)3 = C9H24O6
The molecular formula is C9H24O6
Answer:
Graduated cylinders are designed for accurate measurements of liquids with a much smaller error than beakers. They are thinner than a beaker, have many more graduation marks, and are designed to be within 0.5-1% error. ... Therefore, this more precise relative of the beaker is just as critical to almost every laboratory.
Explanation:
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Answer:
Molecular formula = C₂H₄Cl₂
Explanation:
Molecular formula:
Molecular formula consist of symbols of elements present in compound with numbers of atoms of each element in subscript.
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number .
Given data:
Percentage of hydrogen = 4.07%
Percentage of Cl = 71.65%
Percentage of carbon = 24.27%
Molar mass = 99 g/mol
Molecular formula = ?
Solution:
Number of gram atoms of H = 4.07 / 1.01 = 4.0
Number of gram atoms of Cl = 71.65 / 35.5 = 2.0
Number of gram atoms of C = 24.27 / 12 = 2.0
Atomic ratio:
H : C : Cl
4/2 : 2/2 : 2/2
2 : 1 : 1
C : H : Cl = 1 : 2 : 1
Empirical formula is CH₂Cl.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 12+1×2+ 35.5 = 49.5
n = 99/49.5
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 ( CH₂Cl)
Molecular formula = C₂H₄Cl₂
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