17+7 =25
1/5 = 0.20
3/4= 0.75
25 + 0.20 + 0.75
=25 + 0.95
= 25.95
I hope this helped a bit!:)
Okay, so Sang is standing 20 yards away from one corner, and Jazmin is standing 99 yards away from the same corner. If this is a rectangle (I like visuals, so I'll use them to explain), then:
99ft
A ------------------------- B
| |
20 ft | |
| |
C -------------------------- D
The question is asking you to solve for the diagonal line between points C and B. If you imagine a line there, you actually have the rectangle split into two triangles. So if you have triangle ABC, side CB would be the longest line, or the hypotenuse. That means you can use the Pythagorean Theorem to solve the problem.
A^2 + B^2 = C^2
99^2 + 20^2 = C^2
9,801 + 400 = C^2
10,201 = C^2
Now you solve for the square root of 10,201 to get C.
sqr (10,201) = C
C = 101 yards
Answer:
9 + 15 = 3(3 + 5)
Step-by-step explanation:
The greatest common factor of 9 and 15 is 3.
Factor 3 out of both 9 and 15.
9 + 15 = 3(3 + 5)
<span>Assume 11^10 - 1 = 0 (mod 100) (i.e. 11^10 - 1 is divisible by 100).
11^10 - 1 = 0 (mod 100)
11^10 = 1 (mod 100)
(11^2)^5 = 1 (mod 100)
(121)^5 = 1 (mod 100)
(21)^5 = 1 (mod 100) [the remainder of 121 divided by 100 is 21]
(21^2)^2(21) = 1 (mod 100)
(41)^2(21) = 1 (mod 100)
81(21) = 1 (mod 100)
1701 = 1 (mod 100)
∴ 11^10 - 1 is divisible by 100.</span>
