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Colt1911 [192]
3 years ago
12

Thanks lovely person heres 15 points

Mathematics
2 answers:
marishachu [46]3 years ago
8 0

Answer:

8 units

Step-by-step explanation:

I can count

viktelen [127]3 years ago
7 0

Answer:

thank you

Step-by-step explanation:

░░░░░▐▀█▀▌░░░░▀█▄░░░

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░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob

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▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers

░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take

░░░░░░░▀███▀█░▄░░ Over brainly

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Someone please help me with this!? I’ll give brainliest!!
Studentka2010 [4]
50 fl oz. is the better buy because it cost 0.29 per ounce
5 0
3 years ago
Solve!!!!!!!!!!!! Please
frozen [14]
Begin by multiplying everything by 3 to get rid of the fraction. That gives us -2n \leq 48.  The rule is when you divide by a negative, the direction of the sign changes, so we will end up with n \geq -24.  Because there is a line under the inequality sign, the circle is closed.  So your choices are the second, fourth, and sixth.
6 0
4 years ago
angle U and angle W are vertical angles. If measurement angle u = 6x+11 and measurement angle W = 10x-9, find measurement angle
IgorC [24]

The measure of angle U will be equal to the measure of angle W.

Because W is pronounced "double u", W = 2 * U.

Therefore U = W and U = 2 * W, so both U and W = 0.


Just kidding.

The correct answer is the smallest prime number greater than 40.

8 0
3 years ago
How do you do this question?
attashe74 [19]

Answer:

∑ₙ₌₀°° 8 (-1)ⁿ x⁴ⁿ⁺¹ / (9ⁿ (2n)!)

Step-by-step explanation:

Start with the Maclaurin series for cos x.

cos x = ∑ₙ₌₀°° (-1)ⁿ x²ⁿ / (2n)!

Substitute ⅓ x².

cos (⅓ x²) = ∑ₙ₌₀°° (-1)ⁿ (⅓ x²)²ⁿ / (2n)!

cos (⅓ x²) = ∑ₙ₌₀°° (-1)ⁿ (⅓)²ⁿ x⁴ⁿ / (2n)!

cos (⅓ x²) = ∑ₙ₌₀°° (-1)ⁿ x⁴ⁿ / (9ⁿ (2n)!)

Multiply by 8x.

8x cos (⅓ x²) = ∑ₙ₌₀°° 8x (-1)ⁿ x⁴ⁿ / (9ⁿ (2n)!)

8x cos (⅓ x²) = ∑ₙ₌₀°° 8 (-1)ⁿ x⁴ⁿ⁺¹ / (9ⁿ (2n)!)

5 0
3 years ago
Which expressions are equivalent to \dfrac{2^5}{6^5}
DerKrebs [107]

We have been given an expression \frac{2^5}{6^5}. We are asked to choose the expressions, which are equivalent to our given expression.

Using exponent property \frac{1}{a^n}=a^{-n}, we can rewrite our given expression as:

\frac{2^5}{6^5}=2^5\cdot 6^{-5}

Upon looking at our given choices, we can see that option D is the correct choice.

Let us simplify our given expression.

\frac{2^5}{6^5}=\frac{2^5}{(2\cdot 3)^5}

\frac{2^5}{6^5}=\frac{2^5}{2^5\cdot 3^5}

Upon cancelling out 2^5 from numerator and denominator, we will get:

\frac{2^5}{6^5}=\frac{1}{3^5}

Using exponent property \frac{1}{a^n}=a^{-n}, we will get:

\frac{1}{3^5}=3^{-5}

Therefore, option B is a correct choice as well.

3 0
4 years ago
Read 2 more answers
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