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forsale [732]
3 years ago
5

The accompanying graph shows the revenue from sales of summer sandals. a) At what price will the company receive the maximum amo

unt of revenue? 40+ 45- 35+ Revenue(1005) b) What is the meaning of the increasing region? 20- 18+ 10+ sh c) What is the meaning of the decreasing region? -10 -5+ 10 20 30 40 50 60 70 80 90 11 Selling Price(8) d) What happens to sales if the item is priced at over $85? The cost of carrying this sandal in the store is shown by the linear relation in this graphical model. The intersection points of the graphs show the points where the revenue equals the cost of carrying the item. This is called the breakeven point. Where the revenue graph appears above the cost graph, the store will make a profit. What is the lowest and highest 45+ price the manager can place on the sandals and still make a 40+ profit? 301 Revenue 1005 20+ 15+ 10+ 5+ -10 -5+ 10 20 30 40 30 60 70 80 90 L Seling Price($)
Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0
Hi how are you at this time?
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77+ 2(3x – 5) = 8 – 3(2x + 1)<br> 78 2 + 3(2 -7) – 0 - 13 I 1).
nika2105 [10]

Answer:

-31/6

Step-by-step explanation:

77+2(3x-5)=8-3(2x+1)

77+6x-10=8-6x-3

77-10+6x=8-3-6x

67+6x=5-6x

67+6x-(-6x)=5

67+6x+6x=5

67+12x=5

12x=5-67

12x=-62

x=-62/12

simplify

x=-31/6

3 0
3 years ago
If 5^2x = 1, what is the value of 'x' ?​
SVETLANKA909090 [29]

Answer:

x = 0

Step-by-step explanation:

5^0 is 1, meaning that x must equal to 0 for the answer to be 5^0.

6 0
2 years ago
Read 2 more answers
If tan e = 1.3, what is the value of cot (90° - 9)?
ella [17]

Answer:

A

Step-by-step explanation:

We are given that:

\tan(\theta)=1.3

And we want to find:

\cot(90^\circ -\theta)

Remember that tangent and cotangent are co-functions. In other words, they follow the cofunction identities:

\tan(\theta)=\cot(90^\circ-\theta)\text{ and } \cot(90^\circ-\theta)=\tan(\theta)

Therefore, since tan(θ) = 1.3 and cot(90° - θ) = tan(θ), then cot(90° - θ) must also be 1.3.

Our answer is A.

7 0
3 years ago
PLEASE HELP<br><br><br> ...........
mestny [16]
Hello it’s 25degree brother here’s the solution

8 0
3 years ago
120 books of the same size are packed in 5 boxes. How many such boxes are needed to pack 216 similar books?
monitta

Answer:

lets find how many books are in each box

120/5=24

so 24 book in a box so lets divide for the 216 books

216/24=9

9 boxes

Hope This Helps!!!

7 0
2 years ago
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