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Ilia_Sergeevich [38]
3 years ago
13

Please help, due soon. Use the information provided to write the standard form equation of each circle

Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

The answer is D

Step-by-step explanation:

the standard equation for circle is (x -h)² +(y -k)² = r² which h is the x coordinate, k is the y coordinate, r is radius. In this case, both x coordinate and y coordinate are 0, so the left side of the equation is x² + y², since the radius is √249, the r² is 249. So the equation is x² + y² = 249, and the answer is D.

Hope this will help❤️

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Three people go out to lunch. They decide
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$23.00 each

Step-by-step explanation:

$69 / 3 people = $23 from each person

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What is two thousand divided by 2
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1000

Step-by-step explanation:

2000 : 2 = 1000

8 0
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Is 400​% of 5 less than​ 10, greater than 10 but less than​ 100, or greater than​ 100?
Kryger [21]

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4 0
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Read 2 more answers
add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s
Molodets [167]
<h2>Perfect Squares</h2>

Perfect square formula/rules:

  • a^2+2ab+b^2=(a+b)^2
  • a^2-2ab+b^2=(a-b)^2

Trinomials are often organized like ax^2+bx+c.

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

  • Perfect square trinomial: ax^2+bx+(\dfrac{b}{2})^2
  • or ax^2-bx+(\dfrac{b}{2})^2

<h2>Solving the Question</h2>

We're given:

  • c^2-4c

In a trinomial, we're given the ax^2 and bx values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

  • 4 ÷ 2 = 2
  • 2² = 4

Therefore, the term that we can add is + 4.

c^2-4c+4

To write this as the square of a bracketed expression, we can follow the rule a^2-2ab+b^2=(a-b)^2:

(c-2)^2

<h2>Answer</h2>

c^2-4c+4

(c-2)^2

4 0
2 years ago
Subtract -6x^4-3x^2y^2+5y^4−6x
Gnoma [55]

Answer:

8x^4-5x^2y^2-6y^4+6x

Step-by-step explanation:

We are required to subtract -6x^4-3x^2y^2+5y^4-6x \:from \: 2x^4-8x^2y^2-y^4.

[2x^4-8x^2y^2-y^4]-[-6x^4-3x^2y^2+5y^4-6x]

<u>Step 1:</u> Open the bracket, Take note of the signs

[2x^4-8x^2y^2-y^4]-[-6x^4-3x^2y^2+5y^4-6x]\\2x^4-8x^2y^2-y^4+6x^4+3x^2y^2-5y^4+6x

<u>Step 2:</u> Collect like terms

2x^4+6x^4-8x^2y^2+3x^2y^2-y^4-5y^4+6x

<u>Step 3:</u> Simplify

8x^4-5x^2y^2-6y^4+6x

5 0
3 years ago
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