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gogolik [260]
4 years ago
8

Two horses begin at rest. After a few seconds, horse A is traveling with a velocity of 10m/s west, while horse B is traveling wi

th a velocity of 13m/s west. Which horse had greater acceleration?
A. Horse A because its change in velocity was greater than Horse B in the same time.
B. Horse B because its change in velocity was greater than Horse A in the same time.
C. Horse B because its change in velocity was the same as Horse A's, but it took less time.
D. Both horses had the same acceleration.
Physics
2 answers:
Sliva [168]4 years ago
5 0
The answer is B because 13 m/s is a greater acceleration than 10 m/s in the same amount of time.
creativ13 [48]4 years ago
4 0

The answer is B......



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Consider two point charges located on the x axis: one charge, q1= -11.0 nC, is located at x1= -1.675 m; the second charge, q2= 3
Mekhanik [1.2K]

Answer:

Please refer to the figure.

q1 is a negative charge, and q2 and q3 are positive charges. So, the force exerted by q1 on q3 is attractive, and the force exerted by q2 on q3 is repulsive, which means F13 is directed towards left, and F23 is also directed towards left.

F_{13} = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_3}{r_1^2} = \frac{1}{4\pi \epsilon_0}\frac{11\times 10^{-9}\times 47.5\times10^{-9}}{(-1.675 - (-1.18))^2} = 1.92\times 10^{-5}N

F_{23} = \frac{1}{4\pi\epsilon_0}\frac{q_2q_3}{r_2^2} = \frac{1}{4\pi\epsilon_0}\frac{31\times 10^{-9} \times 47.5\times 10^{-9}}{(-1.18 - 0)^2} = 9.5\times 10^{-6}

The net force on q3 is the sum of these two forces:

F_{net} = F_{13} + F_{23} = -1.92\times 10^{-5} + (-19.5\times10^{-6}) = 2.8\times 10^{-5} N

Since both forces are directed towards left, their sign should be negative.

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Which of the following scientists successfully combined human understanding of forces
Studentka2010 [4]

His name his James Maxwell

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Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
USPshnik [31]

Explanation:

S=(V^2-U^2)/2a a=g (gravity) a=10

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3 years ago
John stirs the hot soup with a spoon the heat travels up the spoon to his hand by what process does the heat travel up the spoon
Gemiola [76]

Answer: is<u><em> Second Law of Thermodynamics (conduction)</em></u>.

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Fed [463]

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