The answer to this question is false
Answer:
The current in the small radius loop must be 0.9677 A
Explanation:
Recall that the formula for the magnetic field at the center of a loop of radius R which runs a current I, is given by:
therefore for the first loop in the problem, that magnetic field strength is:
with the direction of the magnetic field towards the plane.
For the second smaller loop of wire, since the current goes counterclockwise, the magnetic field will be pointing coming out of the plane, and will subtract from the othe field. In order to the addition of these two magnetic fields to be zero, the magnitudes of them have to be equal, that is:
Answer:
The impala pushed down the ground with a force of 37.49N
Explanation:
The force at which the impala pushed down the ground can be calculated for using the Newton's second law of motion,
Force = mass × acceleration
Force = mass ×(velocity/time)
Given mass = 25.5kg
Time = 0.21seconds
To get the velocity, we will use one of the equation of motions;
Using v² = u²+2gH
where;
H is the height reached from the ground = 2.5m
g = 9.81m/s²
u is the initial velocity = 0m/s
v is the final velocity=?
Substituting this values to get the final velocity v;
v² = 0²+2(9.81)(2.5)
v² = 49.05
v = √49.05
v = 7.0m/s
Substituting this velocity into the formula for force we have;
Force = 25.5×(7.0/0.21)
Force = 25.5 × 1.47
Force = 37.49N
The impala pushed down the ground with a force of 37.49N
Fnet = mass × acceleration
Fpush (force by the boys) - 40 = (30)(1.5)
Fpush - 40 = 45
Fpush = 45 + 40
Fpush = 85 N
So, the boys are exerting a force of 85 N on the bicycle.
Answer:
V = E * d voltage equals charge on plates * separation
F = E q force on charge q equals electric field * charge
W = F * d work done equals force times the distance moved
From the very first equation, the voltage depends on the distance between the plates - while the electric field remains constant
The <u>potential difference will decrease</u> as the separation of the plates increases because W remains constant - work done in moving test charge from one plate to another is constant - voltage is constant