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CaHeK987 [17]
3 years ago
12

Assuming that the tungsten filament of a lightbulb is a blackbody, determine its peak wavelength if its temperature is 3 200 K.

Physics
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

the peak wavelength when the temperature is 3200 K = 9.05625*10^{-7} \ m

Explanation:

Given that:

the temperature = 3200 K

By applying  Wien's displacement law ,we have

\lambda _mT = 0.2898×10⁻² m.K

The peak wavelength of the emitted radiation at this temperature is given by

\lambda _m = \frac{0.2898*10^{-2} m.K}{3200 K}

\lambda _m= 9.05625*10^{-7} \ m

Hence, the peak wavelength when the temperature is 3200 K = 9.05625*10^{-7} \ m

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In an inductive circuit, when frequency increases, the circuit current decreases and vice versa.

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microwave ovens rotate at a rate of about 6.3 rev/min. what is this in revolutions per second? (you do not need to enter any uni
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The microwave ovens rotate at a rate of about 0.105 rev/s.

The microwave rotation is the number of revolutions in a unit of time. To change the unit for angular velocity, assume that the quantity is multiplied by the unit it has. Then change to the desired units. The angular velocity is denoted by ω and has a magnitude of 6.3 rev/min.

ω = 6.3 rev/min

\omega = 6.3 \times \frac{1 \: rev}{1 \: min}

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\omega = 6.3 \times \frac{1 \: rev}{60 \: seconds}

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Learn more about Angular velocity here: brainly.com/question/29344944

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2 years ago
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Explanation:

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The electrostatic force follows inverse square law. It is inversely proportional to the square of the distance between the charges. It is directly proportional to the product of the charges.

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Unlike charges attract.

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