All categories

3 years ago

Assuming that the tungsten filament of a lightbulb is a blackbody, determine its peak wavelength if its temperature is 3 200 K.

Physics

1 answer:

rosijanka [135]3 years ago

6 0

Answer:

the peak wavelength when the temperature is 3200 K = $9.05625*10^{-7} \ m$

Explanation:

Given that:

the temperature = 3200 K

By applying Wien's displacement law ,we have

$\lambda _m$ T = 0.2898×10⁻² m.K

The peak wavelength of the emitted radiation at this temperature is given by

$\lambda _m$ = $\frac{0.2898*10^{-2} m.K}{3200 K}$

$\lambda _m$ = $9.05625*10^{-7} \ m$

Hence, the peak wavelength when the temperature is 3200 K = $9.05625*10^{-7} \ m$

You might be interested in

What would be some benefits of living on a planet with less surface gravity

zepelin [54]

You could jump high!

3 0

3 years ago

Read 2 more answers

A 60 kg man jumps down from a 0.8 m table. What is the speed when he

Rom4ik [11]

Answer: Speed = 4 m/s

Explanation:

The parameters given are

Mass M = 60 kg

Height h = 0.8 m

Acceleration due to gravity g= 10 m/s2

Before the man jumps, he will be experiencing potential energy at the top of the table.

P.E = mgh

Substitute all the parameters into the formula

P.E = 60 × 9.8 × 0.8

P.E = 470.4 J

As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.

When hitting the ground,

K.E = P.E

Where K.E = 1/2mv^2

Substitute m and 470.4 into the formula

470.4 = 1/2 × 60 × V^2

V^2 = 470.4/30

V^2 = 15.68

V = square root (15.68)

V = 3.959 m/s

Therefore, the speed of the man when hitting the ground is approximately 4 m/s

4 0

3 years ago

A sample of helium has a volume of 12.7 m3. The temperature is raised to 323 K at which time the gas occupies 32.5 m3? Assume pr

jasenka [17]

Answer: The original temperature was

$T_{1}=126.51K$

Explanation:

Let's put the information in mathematical form:

$V_{1}=12.7m^{3}$

$T_{1}=?$

$V_{2}=32.5m^{3}$

$T_{2}=323K$

$P_{1}=P_{2}=3atm$

If we consider the helium as an ideal gas, we can use the Ideal Gas Law:

$PV=nRT$

were <em>R</em> is the gas constant. And <em>n</em> is the number of moles (which we don't know yet)

From this, taking $R=0.08205746\frac{atm.l}{mol.K}$ , we have:

$n=\frac{P_{2}V_{2}}{RT_{2}}$

⇒ $n=3.67mol$

Now:

$T_{1}=\frac{P_{1}V_{1}}{nR}$

⇒ $T_{1}=126.51K$

7 0

3 years ago

Read 2 more answers

If a body p with a positive charge is placed in contact with a body q (initially uncharged), what will be the nature of the char

uysha [10]

If a body p with a positive charge is placed in contact with a body q (initially uncharged), then the nature of charge gained by q must be positive, because rubbing an uncharged body with a charged body or placed in contact with a positive charged body, helps gain a charge to the uncharged body.

There are a variety of methods to charge an object. One method is known as induction. In the induction process, a charged object is brought near but not touched to a neutral conducting object.

Let's know, how a element gain positive charge?

A positive charge occurs when the number of protons exceeds the number of electrons. A positive charge may be created by adding protons to an atom or object with a neutral charge. A positive charge also can be created by removing electrons from a neutrally charged object.

To learn more about Positive charge here

brainly.com/question/2903220

#SPJ4

5 0

2 years ago

if the radius of the capillary tube is doubled, what changes will take place in the hieght of rise of liquid with capacity tube

tangare [24]

Explanation:

The height of the rise of liquid with capillary tube is given by the formula as follows :

$h=\dfrac{2S\cos\theta}{r\rho g}$

Where

r is radius

It is clear that the height of the rise of liquid is inversely proportional to the radius of the capillary tube.

If the radius of the capillary tube is doubled, it means the height of rise of liquid with capillary tube become half.

5 0

2 years ago