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Brilliant_brown [7]
3 years ago
5

What was also changed in the "Levers" lab when the position of the fulcrum was changed?

Physics
1 answer:
erastova [34]3 years ago
4 0

Effort force

Explanation:

When the potion of fulcrum and weight is changed, the mechanical advantage changes.Increasing the distance between the fulcrum and the effort, there is a proportion increase in effort required to lift a load.The ration of the distance from the fulcrum to the position of input and output application gives the mechanical advantage in levers when losses due to friction are not considered.

Learn More

Mechanical advantage in Levers : brainly.com/question/11600677

Keywords : Levers, fulcrum, position

#LearnwithBrainly

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7 0
3 years ago
ou purchase a rectangular piece of metal that has dimen- sions 5.0 * 15.0 * 30.0 mm and mass 0.0158 kg. The seller tells you tha
Natalija [7]

Answer: 7022.2kg/m³, yes, I was cheated

Explanation:

Density of an object is defined as the ratio of the mass of the object to its volume. Mathematically;

Density = Mass/Volume

Note that the unit of both mass and volume must be standard unit.

Given mass = 0.0158kg

Dimension of the metal = 5mm×15mm×30mm

Note that 1mm = 0.001m

The volume of the metal will be

0.005×0.015×0.03

= 0.00000225m³

Density = 0.0158/0.00000225

Average density of the metal = 7022.2kg/m³

Since the standard density of Gold is 19,320kg/m³ and is higher than the density prescribed for me, it shows the I was cheated.

4 0
3 years ago
What term was used to describe the final digit
xxMikexx [17]

Answer:

Significant digits (also called significant figures or “sig figs” for short) indicate the precision of a measurement. A number with more significant digits is more precise. For example, 8.00 cm is more precise than 8.0 cm.

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Ostrovityanka [42]

The correct answer is:

Work is negative, the environment did work on the object, and the energy of the system decreases.

In fact, the work-energy theorem states that the work done by the system is equal to its variation of kinetic energy:

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In this problem, the variation of kinetic energy \Delta K is negative (because the final velocity is less than the initial velocity), so the work is negative, and this means that the environment did work on the object, and its energy decreased.

3 0
3 years ago
Read 2 more answers
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