The "Ideal Gas Law Equations" is
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or <u>
n</u>umber (in moles)
R= 8.3145
or
T= Temperature (In Kelvin)
Plug into the equation and you're good!
If your teacher cares about sig figs,
2 sig figs (significant figures)
For other units of pressure,
1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar<u />
Answer: Km = 10μM
Explanation: <u>Michaelis-Menten constant</u> (Km) measures the affinity a enzyme has to its substrate, so it can be known how well an enzyme is suited to the substrate being used. To determine Km another value associated to an eznyme is important: <em>Turnover number (Kcat)</em>, which is the number of time an enzyme site converts substrate into product per unit time.
Enzyme veolcity is calculated as:
![V_{0} = \frac{E_{t}.K_{cat}.[substrate]}{K_{m}+[substrate]}](https://tex.z-dn.net/?f=V_%7B0%7D%20%3D%20%5Cfrac%7BE_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D%7D%7BK_%7Bm%7D%2B%5Bsubstrate%5D%7D)
where Et is concentration of enzyme catalitic sites and has to have the same unit as velocity of enzyme, so Et = 20nM = 0.02μM;
To calculate Km:
![V_{0}*K_{m} + V_{0}*[substrate] = E_{t}.K_{cat}.[substrate]](https://tex.z-dn.net/?f=V_%7B0%7D%2AK_%7Bm%7D%20%2B%20V_%7B0%7D%2A%5Bsubstrate%5D%20%3D%20E_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D)
![K_{m} = \frac{E_{t}.K_{cat}.[substrate]-V_{0}*[substrate]}{V_{0}}](https://tex.z-dn.net/?f=K_%7Bm%7D%20%3D%20%5Cfrac%7BE_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D-V_%7B0%7D%2A%5Bsubstrate%5D%7D%7BV_%7B0%7D%7D)
Km = 10μM
<u>The Michaelis-Menten for the substrate SAD is </u><u>10μM</u><u>.</u>
Answer:
Liquids in a form of mixture has less weight as compared to sum of all liquid's weight due to release of gases.
The combined weights of several liquids mixed in an open flask be less than the sum of all the weights of the liquids because when the reaction occurs new products are formed and also some gases which releases in the atmosphere.
These gases also contribute in the weight of the product so when it is released the weight of the mixture of liquids are less than the sum of the weights of all liquids so we can conclude that liquids in a form of mixture has less weight as compared to sum of all liquid's weight.
Explanation:
Answer =B) folding of rock
To find moles : moles= Mass (C₄H₂O₄) / RFM (C₄H₂O₄)
so moles = 147.7 / 114 = <span>1.2956mol
hope that helps </span>
