The standard unit is KW/hr, = 1,000W/hr.
(85 + 60) = 145W.
You need to find its fraction of 1,000W., so (145/1000) = 0.145 KWH.
(0.145 x 10p) = 1.45p. per hr.
        
             
        
        
        
Answer: V = 15 m/s
Explanation:
As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,
F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz
Using doppler effect formula 
F = C/ ( C - V) × f
Where 
F = observed frequency 
f = source frequency 
C = speed of light = 3×10^8
V = speed of the car
Substitute all the parameters into the formula 
2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10
2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)
1.000000049 = 3×10^8/(3×10^8 - V)
Cross multiply 
300000014.7 - 1.000000049V = 3×10^8
Collect the like terms 
1.000000049V = 14.71429
Make V the subject of formula 
V = 14.71429/1.000000049
V = 14.7 m/s
The speed of the car is 15 m/s approximately 
 
        
             
        
        
        
Answer:
option C
Explanation:
given,
diameter of circular room = 8 m
rotational velocity of the rider = 45 rev/min
                   = 
                   =4.712 rad/s
here in this case normal force is equal to centripetal force
 N = m r ω²
 N = m x 4 x 4.712²
 N = 88.83m
frictional force = μ N
     = 88.83m x μ
now, for the body to not to slide
gravity force is equal to frictional force
 m g = 88.83 m x μ
 g = 88.83 x μ
 9.8 = 88.83 x μ
  μ = 0.11
hence, the correct answer  is option C
 
        
             
        
        
        
Answer:
The kinetic energy of the ejected electrons increases.
Explanation:
As we know that electrons are only ejected from a metal surface if the frequency of the incident light increases the work function of the metal. If the frequency of the incident light is less than the work function of the metal no matter how intense the beam the electrons will not be ejected from the surface.
Using conservation of energy principle we have
 
 
If we increase the intensity  of incident light the term on the LHS of the above equation increases this increase appears in the kinetic energy term in RHS of the equation since  remains constant.
 remains constant.