All categories

3 years ago

What will be the time period of simple pendulum at the center of earth

Physics

1 answer:

Furkat [3]3 years ago

7 0

Answer:

As g=0 at the centre of earth the time period becomes infinite as T=2pi/underoot g. At center of earth, r = 0 & hence g = 0. Time period of a simple pendulum is T = 2π sqrt (1/g).

Explanation:

You might be interested in

A toy floats in a swimming pool. The buoyant force exerted on the toy depends on the volume ofa. none of these choices.b. all th

Citrus2011 [14]

Answer:c

Explanation:

The buoyancy force on toy depends upon the volume of toy under pool water.

According to Archimedes principle buoyant force on a floating body depends upon the weight of displaced liquid by object.

Buoyancy force is given by

$F_b=\rho _f\times V\times g$

where $\rho _f$ =density of fluid

V=volume of object under water

g=acceleration due to gravity

6 0

4 years ago

If we represent the solar system on a scale that allows us to walk from the Sun to Pluto in a few minutes, then

aksik [14]

Answer:

b. the planets are marble-size or smaller and the nearest stars are thousands of miles away

Explanation:

The correct answer for the question is option b because if the distance between sun and Pluto is any scale is made equivalent to a walking distance of some minutes then the size of planets will be equivalent to the size of marbles and the nearest stars that is present in Alpha centauri triple star system(4.5 light years away) will be approximately thousands of miles away from us.

4 0

3 years ago

Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2

Bess [88]

Answer:

The acceleration of $M_2$ is $a = 0.7156 m/s^2$

Explanation:

From the question we are told that

The mass of first block is $M_1 = 2.25 \ kg$

The angle of inclination of first block is $\theta _1 = 43.5^o$

The coefficient of kinetic friction of the first block is $\mu_1 = 0.205$

The mass of the second block is $M_2 = 5.45 \ kg$

The angle of inclination of the second block is $\theta _2 = 32.5^o$

The coefficient of kinetic friction of the second block is $\mu _2 = 0.105$

The acceleration of $M_1 \ and\ M_2$ are same

The force acting on the mass $M_1$ is mathematically represented as

$F_1 = T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1$

=> $M_1 a = T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1$

Where T is the tension on the rope

The force acting on the mass $M_2$ is mathematically represented as

$F_2 = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

$M_2 a = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

At equilibrium

$F_1 = F_2$

$T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

making a the subject of the formula

$a = \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}$

substituting values $a = \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}$

=> $a = 0.7156 m/s^2$

3 0

4 years ago

Of gold oxygen iron and sulfur which is a renewable source

matrenka [14]

Oxygen..................................

6 0

3 years ago

Two projectiles are in flight at the same time. The acceleration of one relative to the other: A. is always 9.8 m/s2 B. can be a

zepelin [54]

Answer:

D. Is Zero

Explanation:

The acceleration on projectiles travelling through the air is only caused by gravity. This equal 9.81 m/s^2.

Other than gravity, there is no source of acceleration. Only air resistance causes projectiles of different surface areas to slow down at different rates.

As friction is not considered here (because no statement about surface areas of projectiles is given in the question), we do not need to consider it's effects and thus ONLY GRAVITY MATTERS.

Since gravity acting on both objects is equal, they have no acceleration relative to one another.

5 0

3 years ago

What will be the time period of simple pendulum at the center of earth​

What will be the time period of simple pendulum at the center of earth