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3 years ago

Consider this right angle

Mathematics

2 answers:

Zarrin [17]3 years ago

8 0

To solve this problem you must apply the proccedure shown below:

1. You have that the ratio of the tangent function is:

tan(angle)=opposite/adjacent

2. Keeping this on mind, you have:

tan(A)=12/5

Therefore, the answer is:

tan(A)=12/5

Sunny_sXe [5.5K]3 years ago

4 0

Hello!

First you have to label the sides of the triangle

The hypotenuse is the longest side
The opposite side is the side opposite of the angle
The adjacent side is the third side

Find tangent you do opposite / adjacent

The opposite side is 12
The adjacent side is 5

Put in the numbers

The answer is D) 12/5

Hope this helps!

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Find the area of the region bounded by the curves y = sin^-1(x/6), y = 0, and x = 6 obtained by integrating with respect to y. Y

Nezavi [6.7K]

y = sin^-1(x/6), y = 0, and x = 6 so look at this
since x = 6 "(x/6)" would be (6/6)
Hope this helps and mark as brainliest please!

8 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

We can conclude that the change to the face 3 affects the value of P(Odd Number)

7 0

3 years ago

. Use Lagrange multipliers to find the maximum and minimum values of the function, f, subject to the given constraint, g. (Place

zzz [600]

Answer:

Minimum value of f(x, y, z) = (1/3)

Step-by-step explanation:

f(x, y, z) = x⁴ + y⁴ + z⁴

We're to maximize and minimize this function subject to the constraint that

g(x, y, z) = x² + y² + z² = 1

The constraint can be rewritten as

x² + y² + z² - 1 = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = x⁴ + y⁴ + z⁴ - λ(x² + y² + z² - 1)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points, each of the partial derivatives is equal to 0.

(∂L/∂x) = 4x³ - λx = 0

λ = 4x² (eqn 1)

(∂L/∂y) = 4y³ - λy = 0

λ = 4y² (eqn 2)

(∂L/∂z) = 4z³ - λz = 0

λ = 4z² (eqn 3)

(∂L/∂λ) = x² + y² + z² - 1 = 0 (eqn 4)

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

4x² = 4y²

4x² - 4y² = 0

(2x - 2y)(2x + 2y) = 0

x = y or x = -y

Also,

4x² = 4z²

4x² - 4z² = 0

(2x - 2z) (2x + 2z) = 0

x = z or x = -z

when x = y, x = z

when x = -y, x = -z

Hence, at the point where the box has maximum and minimal area,

x = y = z

And

x = -y = -z

Putting these into the constraint equation or the solution of the fourth partial derivative,

x² + y² + z² = 1

x = y = z

x² + x² + x² = 1

3x² = 1

x = √(1/3)

x = y = z = √(1/3)

when x = -y = -z

x² + y² + z² = 1

x² + x² + x² = 1

3x² = 1

x = √(1/3)

y = z = -√(1/3)

Inserting these into the function f(x,y,z)

f(x, y, z) = x⁴ + y⁴ + z⁴

We know that the two types of answers for x, y and z both resulting the same quantity

√(1/3)

f(x, y, z) = x⁴ + y⁴ + z⁴

f(x, y, z) = (√(1/3)⁴ + (√(1/3)⁴ + (√(1/3)⁴

f(x, y, z) = 3 × (1/9) = (1/3).

We know this point is a minimum point because when the values of x, y and z at turning points are inserted into the second derivatives, all the answers are positive! Indicating that this points obtained are

S = (1/3)

Hope this Helps!!!

6 0

2 years ago

A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tr

frozen [14]

Answer:

The original height of the tree is 18 m.

Step-by-step explanation:

Please see attached photo for explanation.

From the diagram, we shall determine the value of 'x'. This can be obtained by using the pythagoras theory as follow:

x² = 5² + 12²

x² = 25 + 144

x² = 169

Take the square root of both side

x = √169

x = 13 m

Finally, we shall determine the original height of the tree. This can be obtained as follow.

From the question given above, the tree was broken from a height of 5 m from the ground which form a right angle triangle with x being the Hypothenus as illustrated in the diagram.

Thus, the original height of the will be the sum of 5 and x i.e

Height = 5 + x

x = 13 m

Height = 5 + 13

Height = 18 m

Therefore, the original height of the tree is 18 m.

3 0

2 years ago

Which is smaller-21/35, 7/5

Paladinen [302]

Answer:

-21/35

Step-by-step explanation:

So, 7/5 is a postive number, since it doesn't have a negative - sign in front of it. On the other hand, -21/35 does. Knowing this, we can conclude that -21/35 is smaller than 7/5.

If you want another way of thinking about it, just guessing, what is 7/5? Well, 7 is bigger than 5, so it must be at least 1. On the other hand, with -21/35, the -21 doesnt look like its bigger than 35, so it must be smaller than 1.

Answer:

-21/35 is smaller than 7/5

Ti⊂k∫∈s ω∅∅p

3 0

3 years ago

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