Answer:
C18H38(s) + O2(g) → CO₂(g) + H₂O(g).
Explanation:
C₁₈H₃₈ is called Octadecane and it is an Alkane as the molecular formula follows the general formula of Alkanes which is CnH2n+2 .
C₁₈H₃₈ reacts with Oxygen and forms Carbon Dioxide (CO₂) and Water (H₂O).
We can say that on oxidation Octadecane gives Carbon Dioxide (CO₂) and Water (H₂O) because on passing Oxygen over Octadecane the above products are formed.
C18H38(s) + O2(g) → CO₂(g) + H₂O(g).
5.75 Grams per cm^3
You do mass divided by volume
