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ki77a [65]
3 years ago
6

A solution is prepared by dissolving 4.85 g of HCl into enough water to make 2.50 L of a solution

Chemistry
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

0.0532 M

Explanation:

Just did the test :)

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Drupady [299]

Answer: 1.70942

Explanation:

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Wertyujikl;lkmjnbvcdsdertyuikmnbvcxs sdfrtyuiolkmnbvcxzasedrty hgrewazxcvbn
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Explanation:

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3 years ago
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If the following elements were to form ions, they would attain the same number of electrons as which noble gas? As , Be , O , S
Verdich [7]
<h3><u>Answer;</u></h3>

As, & Sr --------[Kr]

Be ------------------- [He]

O, & Mg ----------[Ne]

S, & Ca -------------[Ar]

<h3><u>Explanation</u></h3>
  • <u>The Be+ ion has 2 electrons, just like He. The ions Mg2+ and O2− each has 10 electrons like Ne. </u>
  • <u>The S2− and Ca2+ each has 18 electrons like Ar. The ions As3− and Sr+ each have 36 electrons like Kr.</u>
  • <u>Atoms of elements lose or gain electrons to attain a stable configuration which is equivalent to the configuration of noble gases.</u>
  • When atoms lose or gain electrons they form ions, which are either positively charged or negatively charged. When atoms lose electrons they form positively charged ions while if they gain electrons the form negatively charged ions

4 0
4 years ago
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Can some one please help to understand this problem??<br><br><br>​
Rama09 [41]

Answer:

mercury, magnesium, water and gasoline.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

The liquid with higher density will sink in bottom while the liquid with lower density will float.

In given samples,

density of water = 1 g/mL

density of mercury = 13.6 g/mL

density of gasoline = 0.70 g/mL

density of magnesium = 1.7 g/mL

So on the basis of given density values mercury will sink in bottom then above it magnesium will present than water and above on these three gasoline will present.

6 0
3 years ago
When gaseous ammonia is passed over solid copper(Il) oxide at high temperatures, nitrogen gas is formed. 2NH3(g) + 3CuO(s)---&gt
antoniya [11.8K]

Answer:

copper(ll)oxide

Explanation:

Limit reagent is a reagent that finished thereby stopping the reaction.

2NH3(g) + 3CuO(s)---> N2(g) + 3Cu(s) + 3H20(g)

molar mass of of ammonia = 17.031 × 2  (stiochiometry mole) = 34.06 g/mol

molar mass of CuO = 79.545 × 3 = 238.635 g/mol

molar mass of Nitrogen gas =  28.0134 g/mol

34.06 g of NH3   need 238.635 of CuO to produce 28.0134 of Nitrogen gas

238.635g produce 28.0134 g

x gram of CuO  produce 26 gram of Nitrogen gas

x gram = ( 26 × 238.635 ) / 28.0134 = 221.484 g

also

34.06  g of ammonia produces 28.0134g of nitogen gas

y gram of ammonia produce 26g

y gram = (26× 34.06) / 28.0134 g = 31.61 g

but the 34 g of ammonia was used in the reaction and 31.61 reacted leaving and 2.39 g of ammonia gas

The limiting reagent therefore is copper(ll)oxide

6 0
4 years ago
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