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pshichka [43]
3 years ago
10

Predict the formulas of the products and classify the following reaction:

Chemistry
1 answer:
Zina [86]3 years ago
3 0

Answer:

C18H38(s) + O2(g) → CO₂(g) + H₂O(g).

Explanation:

C₁₈H₃₈ is called Octadecane and it is an Alkane as the molecular formula follows the general formula of Alkanes which is CnH2n+2 .

C₁₈H₃₈ reacts with Oxygen and forms Carbon Dioxide (CO₂) and Water (H₂O).

We can say that on oxidation Octadecane gives Carbon Dioxide (CO₂) and Water (H₂O) because on passing Oxygen over Octadecane the above products are formed.

C18H38(s) + O2(g) → CO₂(g) + H₂O(g).

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zlopas [31]

Answer:

A. modern organisms closely resembling fossils

Explanation:

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Hence, the correct answer is "A. modern organisms closely resembling fossils".

7 0
3 years ago
Napisz równania reakcji chemicznych w formie cząsteczkowej, jonowej i jonowej skróconej. Podkreśl wzory soli trudno rozpuszczaln
Ierofanga [76]

Answer:idioma equivocado ????

Explanation:

3 0
4 years ago
Which subatomic particles are found in the nucleus of an oxygen atom?
Ipatiy [6.2K]

Answer:

the answer is protons and neutrons

Explanation:because

5 0
3 years ago
If a nanometer is one billionth of a meter (0.000 000 00 1 m), how many nanometers are there in one meter?
Anit [1.1K]

Answer:

One billion

Explanation:

A nanometer is a BILLIONTH of a meter which means it takes one billion to equal a meter

6 0
3 years ago
How many grams of AgNO3 are needed to prepare a 75.00 mL solution that is 6.5% (m/v)?
FrozenT [24]

Answer:

Volume of AgNO₃ = 4.9 ml (Approx)

Explanation:

Given:

Total solution = 75 ml

Volume of AgNO₃ = 6.5%

Find:

Volume of AgNO₃

Computation:

Volume of AgNO₃ = Total solution x Volume of AgNO₃

Volume of AgNO₃ = 75 x 6.5%

Volume of AgNO₃ = 4.875

Volume of AgNO₃ = 4.9 ml (Approx)

5 0
3 years ago
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