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3 years ago

Type the correct answer in the box.

Chemistry

2 answers:

OlgaM077 [116]3 years ago

7 0

Explanation:

Mass number of an atom means the sum of total number of protons and neutrons present in an atom.

On the other hand, atomic number is the total number of protons present in an atom.

Therefore, mass number of phosphorous is 30 g/mol whereas atomic number of phosphorous is 15 g/mol.

Thus, the mass of 1 mole of phosphorus atoms is 30 grams.

tatiyna3 years ago

4 0

the mass of 1 mole of phosphorus atoms is approximately 30 g

hope this helps :)

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hen adding a solute to water, the vapor pressure will __________ and the boiling point will __________.

Nina [5.8K]

Answer:

decrease, increase

Explanation:

6 0

3 years ago

In a gas grill, 29 lbs propane C3H8 are

dimulka [17.4K]

Answer : The mass of combustion products formed are 134 lbs.

Explanation :

The balanced chemical reaction will be:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

Given :

Mass of $C_3H_8$ = 29 lbs = 13154.2 g

conversion used : 1 lbs = 453.592 g

Molar mass of $C_3H_8$ = 44 g/mole

First we have to calculate the moles of $C_3H_8$ .

$\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{13154.2g}{44g/mole}=298.9moles$

Now we have to calculate the moles of $CO_2$ and $H_2O$ .

From the balanced chemical reaction we conclude that,

As, 1 mole of $C_3H_8$ react to give 3 moles of $CO_2$

So, 298.9 mole of $C_3H_8$ react to give $298.9\times 3=896.7$ moles of $CO_2$

and,

As, 1 mole of $C_3H_8$ react to give 4 moles of $H_2O$

So, 298.9 mole of $C_3H_8$ react to give $298.9\times 4=1195.6$ moles of $H_2O$

Now we have to calculate the mass of $CO_2$ and $H_2O$ .

Molar mass of $CO_2$ = 44 g/mole

Molar mass of $H_2O$ = 18 g/mole

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass }CO_2$

$\text{Mass of }CO_2=896.7mole\times 44g/mole=39454.8g=86.98lbs$

and,

$\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass }H_2O$

$\text{Mass of }H_2O=1195.6mole\times 18g/mole=21520.8g=47.44lbs$

The total mass of products = Mass of $CO_2$ + Mass of $H_2O$

The total mass of products = 86.98 + 47.44 = 134.42 ≈ 134 lbs

Therefore, the mass of combustion products formed are 134 lbs.

6 0

3 years ago

Tju [1.3M]

I believe that is false.

5 0

3 years ago

Which aqueous solution has a freezing point closer to its predicted value, 0.01 m NaBr or 0.01 m MgCl₂? Explain

emmasim [6.3K]

NaBr will behave more ideally and have an actual freezing point closer to its predicted (theoretical) value.

<h3>What is freezing point?</h3>

The temperature at which a liquid turns into a solid under normal air pressure is known as the freezing point.

NaBr in water dissociates to $Na^{+}$ and $Br^{-}$ (two particles) while $MgCl_{2}$ dissociating to $Mg^{2+}$ two $Br^{-}$ (three particles). There is a difference between a theoretical boiling/freezing point and an experimentally determined one and the primary cause of this phenomenon is the formation of positive ions on top of negative ones and vice versa, creating an ionic environment with a net opposite charge.

In such a setting we can conclude univalent ions will behave more ideally (bivalent ions have a 'greater' charge and are therefore affecting the solution interactions more). Also, since NaBr dissociates to only two particles, we can conclude it will behave more ideally. Finally, based on these two reasons, we can conclude that out of the two given compounds, NaBr will behave more ideally and have an actual freezing point closer to its predicted (theoretical) value.

To know more about freezing point, visit: brainly.com/question/3121416

#SPJ4

4 0

1 year ago

What are primary methods of chemical exposure?

S_A_V [24]

1. inhalation 2. ingestion 3. skin contact. Hope this helps

4 0

3 years ago