The <em>complement </em>C'<em> </em>of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.
Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:
If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the <em>even numbers </em>between 1 and 16:
Answer:
3
Step-by-step explanation:
Note the general factorisation of a difference of 2 squares is
a² - b² = (a + b)(a + b)
Given
(- 5x - 3)(- 5x + ?)
Then ? = 3 so that the complete factors are
(- 5x - 3)(- 5x + 3)
Answer:
x² -3x - 54
Step-by-step explanation:
given roots of a polynomial are 9 and -6
this means that (x-9) and (x+6) are factors of the polynomial.
To get the polynomial with the least degree, simply multiply the two factors to obtain a quadratic expression (degree 2)
(x-9) (x+6)
= x² + 6x -9x -54
= x² -3x - 54
Answer:
<em>(a); (b); (d)</em>
Step-by-step explanation:
ΔGHK ≅ ΔMNP
(a). GH = MN
(b). KH = PN
(d). ∠G ≅ ∠ M
